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guajiro [1.7K]
3 years ago
12

You are asked to draw a triangle with side length of 6 inches and 8 inches.What is the longest whole number length that your thi

rd side can be?
Mathematics
2 answers:
irina1246 [14]3 years ago
7 0
A² + b² = c², c being the longest side.

6² + 8² = c²

c² = 36 + 64 

c² = 100

c = √100

c = 10 inches

Answer: The longest length of the 3rd side is 10 inches.
Mice21 [21]3 years ago
5 0
l=6inch and 8inch\\c^2=a^2+b^2\\c = \sqrt{(6^2+8^2)}=10inch
use the pathgorean theorem in order to get the longest side of the given triangle.
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Answer:

The answer is C. The translation of a line is a pair of parallel lines.

Step-by-step explanation:

A, B, and D are true. C is <em>not</em> true, and therefore the correct answer.

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At the Henry Doorly Zoo the giraffe grew from 24 inches to 60 inches long in five months. Find
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Answer:

150%

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Step-by-step explanation:

We start by calculating the percentage increase

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3 years ago
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nordsb [41]

Step-by-step explanation:

The given equation is

(3x^{2}-y)dx+(4y^{3}-x)dy=0\\M(x,y)dx+N(x,y)dy=0

As a check for exactness we have

\frac{\partial N}{\partial x}=\frac{\partial M}{\partial y}\\\\\therefore \frac{\partial N}{\partial x}=\frac{\partial (4y^{3}-x)}{\partial x} =-1\\\\\frac{\partial M}{\partial y}=\frac{\partial (3x^{3}-y)}{\partial y} =-1\\\\\therefore \frac{\partial N}{\partial x}=\frac{\partial M}{\partial y}=-1

Hence the given equation is an exact differential equation and thus the solution is given by

thus the solution is given by

u(x,y)=\int M(x,y)\partial x+\phi (y)\\\\u(x,y)=\int (3x^{2}-y)\partial x+\phi (y,c)\\\\u(x,y)=x^{3}-xy+\phi (y,c)\\\\

Similarly we have

u(x,y)=\int N(x,y)\partial y+\phi (x,c)\\\\u(x,y)=\int (4y^{3}-x)\partial y+\phi (x,c)\\\\u(x,y)=y^{4}-xy+\phi (x,c)\\\\

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Hence the solution becomes

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1^{3}+1^{4}-1=c\\\\\therefore c=1

thus solution is

u(x,y)=x^{3}+y^{4}-xy=1

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