So
Total cost of the workbooks is d
And the number of workbooks is t
Therefore d = 95
95=19t
t=95/19=5
5 workbooks
Answer:
Only the x-value changes.
Step-by-step explanation:
When a point is reflected over the y-axis, it is the x-axis number that will flip it's sign.
When a point is reflected over the x-axis, it is the y-axis number that will flip it's sign.
~
Answer:
100 students
Step-by-step explanation:
10% of students in 7th grade ----- 10 students
<em>Divide</em><em> </em><em>by</em><em> </em><em>1</em><em>0</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>
1% of students in 7th grade ----- 10 ÷10= 1 student
<em>×</em><em>100</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>
100% of students in 7th grade ----- 1 ×100= 100 students
If it needs to be a rectangle, then the rectangle with the smallest perimeter for
a given area is the square. He needs 32 feet of fence, and should fence off a
square that's 8 x 8 .
But if he's willing to go to the trouble, the perimeter of a circle with the same area
is even less than the square.
A = (pi) (R²)
R = √(64/pi).
Circumference = (2 pi) (R) = 2 pi √(64/pi) = √(256 pi) = 28.359 (rounded).
That's 11.4% less fence to buy, for a circular run.
But on the other hand, what have you got against the dog ? One of
the two main purposes of a dog run is to give the dog a place to <u>run</u>.
Minimizing the perimeter also minimizes the distance where he can get
up some speed and run in a straight line ... freeing up his hips, clearing
the cobwebs from his brain, smelling the air, keeping his claws nice and
worn down. With the emotional well-being of the dog in mind, I'd expect
you'd want to give him the <u>maximum</u> possible straight route inside the
run, which, unfortunately, also maximizes the amount of fence that Malcolm
has to provide.
But I digress. The math is done. The question is answered.
This case is closed.
Answer:the middle one
B is the answer
Step-by-step explanation:
