Answer: ionotropic; metabotropic
Explanation:
A receptor can directly open the channel and exerts an ionotropic effect. The ionotropic effect takes place by the help of ionotropic receptors. These receptors are membrane bound receptor proteins which responds by the bonding of the ligand.
Due to ligand binding the channel opens and allows the movement of ions into the cells which helps in either increasing or decreasing the action potential.
The receptors can also bind to the ligand and produce metabotropic effect which means by the second messenger.
Answer:
<h2>
Interphase : divided into three phases, i) G1 phase, ii) S phase and iii) G2 phase.</h2><h2>Mitotic phase: i) prophase, ii) metaphase, iii) anaphase and v) telophase.</h2>
Explanation:
interphase : divided into three phases, i) G1 phase, ii) S phase and iii) G2 phase.
G1 phase: cell decide whether to divide or not and prepare itself for replication of DNA and arrange replication machinery. otherwise it goes to G 0 phase.
S phase: DNA replication occurs in this phase.
G2 phase: cell duplicates all their contents and prepares for mitotic phase.
Mitotic phase:
i) prophase- chromosome condensation occurs,
ii) metaphase - chromosome arranges in meta-plate and spindle binds to each chromosomes at centromere.
iii) anaphase- chromosome separates from sister chromatids.
iv) telophase- chromosome moves to each ends and formation of nuclear membrane begins.
cytokinesis: there is division of cytoplasm and forming two daughter cells.
Answer:
Dissolve 47.025 grams of sucrose in enough water to produce 250 ml of solution.
Explanation:
You need to prepare 250. mL of a 0.550 M aqueous solution of sucrose, C12H22O11 (aq),
which is used frequently in biological experiments.
Based on your answer above, what is the value of x?
Solution:
A 0.550 M aqueous solution contains 0.550 mole of sucrose per liter of solution.
250 ml = 0.250 liter
Thus a 0.250 liter of a 0.550 M aqueous solution of sucrose contains 0.250 * 0.550 = 0.1375 mole of sucrose
Recall:
Mass = number of moles * mass of 1 mole
mass of 1 mole of C12H22O11
= 12(12) + 1(22) + 16(11)
= 144 + 22 + 176
= 342 grams
Mass = 0.1375 * 342 = 47.025 grams of sucrose.
Dissolve 47.025 grams of sucrose in enough water to produce 250 ml of solution.
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