Answer:
Measuring heart rate and noting blood pressure is the answer.
Explanation:
Answer:
1/8
Explanation:
Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.
The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2
The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2
The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2
So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=
1/2 * 1/2 * 1/2 = 1/8
Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.
<span>6 Turns of the Calvin Cycle→ 1 C₆H₁₂O₆
6CO₂ → 1 C₆H₁₂O₆
18 ATP + 12 NADPH → 1 C₆H₁₂O₆
ATP is used elsewhere by the cell.</span>
A, B, D, and E are all wrong. C is the right answer. C is a compound.
A, B, D and E are not unique. A pure substance is something with unique characteristics and if it can be broken down, the result is two or more pure substances. AKA only compounds and elements. This is an easy question so try to study.