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3 years ago

10

Consider a function that describes how a particular car’s gas mileage depends on its speed. What would be an appropriate domain

for this function?

2 answers:

natta225 [31]3 years ago

8 0

Domain are x values (independent variable);

Speed would be independent so what speeds can be used ? -30 mph, 30 mph, 1000 mph?

Can a car go 0 mph?

What is realistic?

I would say 0 greater or equal to x greater than whatever you think is beyond the max that a car can go.

notka56 [123]3 years ago

3 0

Answer:

0 to 100 MPH.

Step-by-step explanation:

Hope this helps!!

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A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0

3 years ago

How would you rename both factors of 61*69

natulia [17]

4209Answer:

Step-by-step explanation:

Magic

5 0

3 years ago

(50 points and brainliest.Need help ASAP)

Aleksandr-060686 [28]

Answer: " 2x (2x - 1) (x + 1) " .

______________________________________

Step-by-step explanation:

______________________________________

Given:

f(x) = 9x³ + 2x² − 5x + 4 ;

g(x) = 5x³ − 7x + 4 ;

______________________________________

What is: f(x) − g(x) ?

______________________________________

Plug in: " 9x³ + 2x² − 5x + 4 " for: " f(x) " ;

and: " (5x³ − 7x + 4) " ; for: "g(x)" ;

______________________________________

→ " f(x) − g(x) =

" 9x³ + 2x² − 5x + 4 − (5x³ − 7x + 4) " .

______________________________________

Rewrite this expression as:

→ " 9x³ + 2x² − 5x + 4 − 1(5x³ − 7x + 4) " .

→ {since: " 1 " ; multiplied by "any value" ; is equal to that same value.}.

______________________________________

Now, let us example the following portion of the expression:

______________________________________

" − 1(5x³ − 7x + 4) "

_____________________________________

Note the "distributive property" of multiplication:

______________________________________

→ a(b + c) = ab + ac ;

______________________________________

Likewise:

→ a(b + c + d) = ab + ac + ad .

______________________________________

As such:

______________________________________

→ " − 1(5x³ − 7x + 4) " ;

______________________________________

= (-1 * 5x³) + (-1 * 7x) + (-1 * 4) ;

= - 5x³ + (-7x) + (-4) ;

= - 5x³ − 7x − 4 ;

_____________________________________

Now, add the "beginning portion of the expression" ; that is:

" f(x) " ; to the expression ; which is:

→ 9x³ + 2x² − 5x + 4 ;

→ as follows:

_______________________________________

→ 9x³ + 2x² − 5x + 4 − 5x³ − 7x − 4 ;

→ {Note that the: " - " sign; that is;

the "negative sign", in the term: " -5x³ " ;

becomes a: " − " sign; that is; a "minus sign" .}.

______________________________________

Now, combine the "like terms" of this expression; as follows:

+ 9x³ − 5x³ = + 4x³ ;

− 5x − 7x = − 2x ;

+ 4 − 4 = 0 ;

______________________________________

and we have:

______________________________________

→ " 4x³ + 2x² − 2x ".

______________________________________

Now, to write this answer in "factored form" :

Note that among all 3 (three) terms in this expression, each term has a factor of "2" . The lowest coefficient among these 3 (three) terms is "2" ; so we can "factor out" a "2".

Also, each of the 3 (three) terms in this fraction is a coefficient to a variable. That variable takes the form of "x". The term in this expression with the variable, "x"; with the lowest degree has the variable: "x" (i.e. "x¹ = x" ) ; so we can "factor out a "2x" (rather than just the number, "2".).

So, by factoring out a "2x" ; take the first term [among the 3 (three) terms in the expression] —which is: "4x³ " .

2x * (?) = 4x³ ? ;'

↔ $\frac{4x^3}{2x} =$ ? ;

→ 4/2 = 2 ;

$\frac{x^{3}}{x} = \frac{x^3}{x^1} = x^{(3-1)} = x^{2}$ ;

As such: 2x * (2x²) = 4x³ ;

___________________________________________

Now, by factoring out a "2x" ; take the second term [among the 3 (three) terms in the expression] — which is: "2x² " .

2x * (?) = 2x² ? ;

↔ $\frac{2x^{2}}{2x} =$ ?

→ 2/2 = 1 ;

→ $\frac{x^{2}}{x} = \frac{x^2}{x^1}= x^{(2-1)} } = x^1 = x$ ;

As such: 2x * (x) = 2x²

__________________________________________

Now, by factoring out a "2x" ; take the third term [among the 3 (three) terms in the expression] — which is: " − 2x " .

2x * (?) = - 2x ;

↔ $\frac{-2x}{2x} =$ -1 ;

As such: 2x * (-1) = − 2x .

__________________________________________

So:

__________________________________________

Given the simplified expression:

→ " 4x³ + 2x² − 2x " ;

We can "factor out' a: " 2x " ; and write the this answer is: "factored form" ; as:

__________________________________________

"2x (2x² + x − 1 ) . "

Now, we can further factor the:

" (2x² + x − 1) " ; portion;

Note: "(2x² + x - 1)" =

2x² + 2x - 1x -1 = (2x -1) + x (2x - 1 ) =

(2x - 1) ( x + 1)

_______________________________________

Now, bring down the "2x" ; and write the Full "factored form" ; as follows:

_______________________________________

→ " 2x (2x - 1) (x + 1) " .

_______________________________________

Hope this helps!

Wishing you the best!

_______________________________________

7 0

3 years ago

Find the slope of line a and line b from two points

Degger [83]

Answer: Line A has a slope of 3/4 and Line B has a slope of 5/6

Step-by-step explanation: Look at the attachment

5 0

3 years ago

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What is the Volume of the square pyramid? (Round to the nearest tenth as needed)

goldenfox [79]

Answer:

5229 mm³

Step-by-step explanation:

Volume of square pyramid

$\sf \boxed{Volume \ of \ the \ square \ pyramid = \dfrac{1}{3}*b^2*H}$

b = base length = 25 mm

H = height

We have to find 'H' using Pythagorean theorem,

slant height (hypotenuse) = 28 mm

leg₁ = base length ÷ 2 = 25÷2 = 12.5

leg₂ = H

H² + (12.5)² = 28²

H² = 784 - 156.25

= 627.75

$\sf H = \sqrt{627.75}$

H = 25.01 mm

$\sf \text{Volume of square pyramid =$\dfrac{1}{3}*25*25*25.1$ }$

= 5229 mm³

$\sf \boxed{\text{Volume of square pyramid = \dfrac{1}{3}*25*25*28}}$

3 0

2 years ago

Read 2 more answers