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alexdok [17]
4 years ago
9

How do I solve this?

Mathematics
1 answer:
Papessa [141]4 years ago
6 0
Nothing to solve...that's a definition or a function. it requires input for a solution.
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if the length of the drawbridge, r, is 20 meters and the point p is 16 meters above the roadway , what is the distance d?
zhenek [66]
I'm assuming that the figure formed in this problem is a right angle. Thus, we need to use the Pythagorean theorem to get the distance or the hypotenuse.

Length = 20 meters
Height = 16 meters

a² + b² = c²

(20m)² + (16m)² = c²
400m² + 256m² = c²
656m² = c²
√656m² = √c²
25.61 m = c

The distance is 25.61 meters.
8 0
4 years ago
20 POINTS
RUDIKE [14]

<em>The correct expressions are as follows:</em>

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 343

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}

\texttt{ }

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }

\boxed { (a ^ b) ^ c = a ^ { b . c } }

\boxed {a ^ b \div a ^ c = a ^ { b - c } }

\boxed {\log a + \log b = \log (a \times b) }

\boxed {\log a - \log b = \log (a \div b) }

<em>Let us tackle the problem!</em>

\texttt{ }

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7^2)^{\frac{7}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7)^{2\times \frac{7}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5} + \frac{14}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{15}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{3}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{343}

\texttt{ }

<em>From the results above, it can be concluded that the correct statements are:</em>

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 343

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}

\texttt{ }

<h3>Learn more</h3>
  • Coefficient of A Square Root : brainly.com/question/11337634
  • The Order of Operations : brainly.com/question/10821615
  • Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

4 0
4 years ago
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Joey's closet is unorganized and contains 7 black short-sleeve shirts, 4 black long-
Ierofanga [76]

Answer:

2/3

Step-by-step explanation:

3 + 7 + 4 = 14

14 + 7 = 21

14/21 = 2/3

6 0
2 years ago
The table shows how the cost of a tractor repair depends on the time needed for the repair.
Kobotan [32]

Answer:

im stupid so im gonna need more info

7 0
3 years ago
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INSTRUCTIONS<br> Solve the division problems<br> Name
skad [1K]

Answer:

13

Step-by-step explanation:

Do the divison! :D It's hard to write out on here, but you can find a lot of other online resources on how to do it, I reccomend Khan Academy.

5 0
3 years ago
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