1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maria [59]
3 years ago
8

20 POINTS

Mathematics
2 answers:
Zepler [3.9K]3 years ago
8 0

Answer:

equivalent

not equivalent

equivalent

not equivalent

-step explanation:

RUDIKE [14]3 years ago
4 0

<em>The correct expressions are as follows:</em>

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 343

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}

\texttt{ }

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }

\boxed { (a ^ b) ^ c = a ^ { b . c } }

\boxed {a ^ b \div a ^ c = a ^ { b - c } }

\boxed {\log a + \log b = \log (a \times b) }

\boxed {\log a - \log b = \log (a \div b) }

<em>Let us tackle the problem!</em>

\texttt{ }

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7^2)^{\frac{7}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7)^{2\times \frac{7}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5} + \frac{14}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{15}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{3}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{343}

\texttt{ }

<em>From the results above, it can be concluded that the correct statements are:</em>

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 343

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}

\texttt{ }

<h3>Learn more</h3>
  • Coefficient of A Square Root : brainly.com/question/11337634
  • The Order of Operations : brainly.com/question/10821615
  • Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

You might be interested in
Find all factors of 27.​
igor_vitrenko [27]

Answer:

all the factors of 27 is 1, 3 ,9,and 27

6 0
2 years ago
Read 2 more answers
In STU, SU =18 and TU =13. Find m
erastova [34]

Answer:

m=22.2

Step-by-step explanation:

By using the Pythagorean’s theorem i.e

hypotenuse^2=opposite^2+adjacent^2

Where

Hypotenuse =unknown

Opposite =18

Adjacent =13

Hyp^2=18^2+13^2

Hyp^2=324+169

Hyp^2=493

Hyp=sqrt 493

Hyp=m=22.2

3 0
3 years ago
A simple random sample of 100 batteries is selected from a process that produces batteries with a mean lifetime of 32 hours and
Brrunno [24]

Answer:

.b. It is one‐half as large as when n = 100.

Step-by-step explanation:

Given that a  simple random sample of 100 batteries is selected from a process that produces batteries with a mean lifetime of 32 hours and a standard deviation of 3 hours.

i.e. s = 0.3

we obtain se of sample by dividing std devitation by the square root of sample size

i.e. s= \frac{3}{\sqrt{n} }

when n =100 this = 0.3 and

when n =400 this equals 0.15

We find that when sample size is four times as large as original, std deviation becomes 1/2 of the original

Correction option is

.b. It is one‐half as large as when n = 100.

7 0
3 years ago
2 FOR 2.20 UNIT RATE
dlinn [17]

Answer: (if your asking for the unit rate of that)

the unit rate is 1.10

5 0
2 years ago
The graph of f(x) = x + 1 is shown in the figure. Find the largest δ such that if 0 &lt; |x – 2| &lt; δ then |f(x) – 3| &lt; 0.4
MArishka [77]
SO what you need to do is:
<span>Start with |f(x) - 3| < 0.4
and plug in f(x) = x+1
to get |f(x) – 3| < 0.4
|x+1 – 3| < 0.4
|x - 2| < 0.4
   -0.4 < x - 2 < 0.4
  -0.4+2 < x < 0.4+2
  1.6 < x < 2.4
So delta would be 2.3
Hope this is what you were looking for
</span>
8 0
3 years ago
Read 2 more answers
Other questions:
  • Which is the rate of change for the interval between 3 and
    12·1 answer
  • The seventh root of x divided by eighth root of x
    14·2 answers
  • HELP PLEASE THANKS......
    12·1 answer
  • ellie brought 60 cookies to class today. 30% of them have mint filing. how many cookies have the mint filling
    15·2 answers
  • TELL ME SOME COOL NAMES THAT YOU'D WANT FOR A WEBSITE!!<br> BEST NAME GETS 25 PTS AND BRAINLIEST.
    15·1 answer
  • HELP ME SOMEBODY PLEASE 8 more
    13·2 answers
  • HELPPPPP!!!!!!!!!!!!!!
    11·2 answers
  • (04.03) The graph shows the amount of money paid when purchasing bags of candy at the zoo: Total cost a Bags of Candy Write an e
    5·1 answer
  • Find the product of the following
    9·1 answer
  • The function f(x), shown in the graph, represents an exponential growth function. Compare the average rate of change of
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!