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Nana76 [90]
4 years ago
13

Which shape could be thought of as being created by stacking congruent polygons?

Mathematics
2 answers:
Amiraneli [1.4K]4 years ago
7 0
You would form a prism. 
yarga [219]4 years ago
3 0

A polygon is composed of three or more line segments ,and when you join these segments ,a closed geometrical shape should form.For example, Equilateral triangle, Square, Regular Pentagon, Regular Hexagon,....

There are many possibilities.

→If you join an Equilateral and three other equilateral triangles having same base length,you will obtain, Equilateral Pyramid.

→If you join Square and four equilateral triangles having same base length,you will obtain, Equilateral Square Pyramid.

→Similarly, if you join Regualr Pentagon and five equilateral triangles having same base length,you will obtain, Equilateral Regular pentagonal Pyramid

→Regular Hexagon+Six equilateral triangles=Equilateral Regular Hexagonal Pyramid

→If you join six congruent squares ,you will get the shape of Prism called Cube.

These are known that is defined shape in mathematics which i have written.You can create many more shapes by yourself.

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Stuck on a couple math questions! Could anyone help me understand them?
Rainbow [258]
1.x×2+24=0
2x=0-24
2x=-24
x=-24/2
x=-12.

9.x×2-9x+3=0
2x-9x=0-3
-7x=-3
x=-3/-7

11.x×2+4x+13=0
2x+4x=0-13
6x=-13
x=-13/6
Hope it is correct and helps u.
7 0
3 years ago
4x−3y=8<br> 4x−y=−8<br> work out x and y
Alexeev081 [22]

Answer:

y = -8

x = -4

okay i hope you got it

6 0
3 years ago
I need help plss I just want to make sure if it’s right or wrong on this answer
kkurt [141]

Answer:

9<BAM OR <ABM

10.BM

11.<BAM AND<ABM

12.CF

13.<CKD

14.<JHF

15.JE ( in only one direction)

8 0
3 years ago
Differentiate<br>y=tan (x^2-5x+6)​
slavikrds [6]

Use the chain rule:

<em>y</em> = tan(<em>x</em> ² - 5<em>x</em> + 6)

<em>y'</em> = sec²(<em>x</em> ² - 5<em>x</em> + 6) × (<em>x</em> ² - 5<em>x</em> + 6)'

<em>y'</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)

Perhaps more explicitly: let <em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6, so that

<em>y(x)</em> = tan(<em>x</em> ² - 5<em>x</em> + 6)   →   <em>y(u(x))</em> = tan(<em>u(x)</em> )

By the chain rule,

<em>y'(x)</em> = <em>y'(u(x))</em> × <em>u'(x)</em>

and we have

<em>y(u)</em> = tan(<em>u</em>)   →   <em>y'(u)</em> = sec²(<em>u</em>)

<em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6   →   <em>u'(x)</em> = 2<em>x</em> - 5

Then

<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>u</em>)

or

<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)

as we found earlier.

5 0
3 years ago
What is the volume if the density of an object is 3.0g/mL and the mass is 15.0g?
adelina 88 [10]
The volume would be 5 because in order to find volume you need to divide mass over density. V=m/d
3 0
3 years ago
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