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kifflom [539]
3 years ago
11

Oliver and Marie are graphing two equations on a coordinate grid. Oliver has graphed the equation y = 2x + 2. If Marie graphs y

= 2x - 3, where will the y-intercept of her graph be in relation to Oliver's graph? A) 3 units lower B) 5 units lower C) 5 units higher D) the same place
Mathematics
2 answers:
saveliy_v [14]3 years ago
7 0

Answer:

B) 5 units lower.

Step-by-step explanation:

We have been given that Oliver has graphed the equation y=2x+2 and Marie graphs y=2x-3. We are asked to find where Marie's graph will be with relation to Oliver's graph.

We can see that both lines are in slope-intercept form of equation: y=mx+b, where,

m = Slope of the line,

b = Initial value or y-intercept.

We can see that both lines have same slope, but y-intercepts for both lines are different.

Since y-intercept is the point, where line crosses y-axis. We can see that Oliver's line will cross y-axis at y=2, while Marie's line crosses y-axis at y=-3.

Since -3 is 5 units below from 2, therefore, y-intercept of Marie's graph be 5 units lower than Oliver's graph and option B is the correct choice.

Irina18 [472]3 years ago
5 0
Oliver : y = 2x + 2......y int is 2
maria : y = 2x - 3.......y int is -3

Maria's y int is 5 units lower then Oliver's y int
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Here's the solution,

<u>figure</u> 1.

by using trigonometry,

=》

\sin(60)  =   \dfrac{5 \sqrt{3} }{y}

=》

\dfrac{ \sqrt{3} }{2}  =  \dfrac{5 \sqrt{3} }{y}

=》

\dfrac{1}{y}  =  \dfrac{ \sqrt{3} }{2 \times 5 \sqrt{3} }

=》

\dfrac{1}{y}  =  \dfrac{1}{10}

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And,

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=》

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So, values are :

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<u>figure</u> 2.

Since, it's an isosceles triangle, w = y,

So, by pythagoras theorem :

=》

{w}^{2}  +  {y}^{2}  = (7 \sqrt{2} ) {}^{2}

=》

{w}^{2}  +  {w}^{2}  = 98

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2 {w}^{2}  = 98

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{w}^{2}  = 49

=》

w =  \sqrt{49}

=》

w = 7

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