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3 years ago

Huw do I combine like terms

Mathematics

1 answer:

dybincka [34]3 years ago

8 0

I'll give you an example

y= 2x+56a-16a+14x

y=16x+40a

you basically just do the letters that are the same together i hope it make sense to you

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Joe bought 15 items for $135. If the 15 items consisted of notebooks that cost $4.50 each and calculators that cost $12.00 each,

Luda [366]

n + c = 15

4.5n + 12c = 135

c = 15 - n

12c = 180 - 12n

180 - 12n + 4.5n = 135

-7.5n = - 45

15n = 90

notebook = 6

6 + c = 15

calculator = 9

6 0

2 years ago

Ill give brainliest and 5 stars and thanks if answer this what is the result of substituting for y in the bottom equation

GREYUIT [131]

We have two set of solutions , ( $\frac{\sqrt{29} }{2}$ , $\frac{\sqrt{29} }{2}$ + 3 ) , ( - $\frac{\sqrt{29} }{2}$ + 3 , - $\frac{\sqrt{29} }{2}$ + 3).

Step-by-step explanation:

We have , the following equations:

$y = x+3$ and $y = x^{2} +2x -4$ . Let's substitute value of y in bottom equation:

⇒ $y = x^{2} +2x -4$

⇒ $x+3 = x^{2} +2x -4$

⇒ $x^{2} +x -7= 0$

Roots of quadratic equation are given by: a = 1, b= 1 , c = -7

$x = \frac{\sqrt{b^{2}-4ac} }{2a}$

⇒ $x = \frac{\sqrt{b^{2}-4ac} }{2a}$

⇒ $x = \frac{\sqrt{1^{2}-4(1)(-7)} }{2(1)}$

⇒ $x = \frac{\sqrt{29} }{2}$ which is actually x = ± $\frac{\sqrt{29} }{2}$ .

We know that $y = x+3$ ,

⇒ y = ± $\frac{\sqrt{29} }{2}$ + 3.

We have two set of solutions , ( $\frac{\sqrt{29} }{2}$ , $\frac{\sqrt{29} }{2}$ + 3 ) , ( - $\frac{\sqrt{29} }{2}$ + 3 , - $\frac{\sqrt{29} }{2}$ + 3).

5 0

3 years ago

What is x if the box is 70in to the 3rd power?

koban [17]

Step-by-step explanation:

I doint know the answer but have a great day today or tomorrow

8 0

3 years ago

What is the t- critical value for the confidence levek of c=92 and 19 degrees of freedom

Nonamiya [84]

Answer:

-1.85

Step-by-step explanation:

On TI-84

invT((1-0.92)/2), 19)

invT(0.04,19)

8 0

4 years ago

What is the answer to thiss

lana [24]

Hi Student!

This question is fairly simple because it gives us an equation and they also give us a value for the variable that is within the equation and they tell us evaluate the expression. So let's plug in the values and solve.

Plug in the values