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alexandr402 [8]

3 years ago

12

Three consecutive integers have a sum of 30. Which equation can be used to find x, the value of the smallest of the three number

s? (x + 1) + (x + 2) = 30 x + (x + 1) + (x + 2) = 30 x (x + 1) (x + 2) = 30 3 x (x + 1) (x + 2) = 30

1 answer:

castortr0y [4]3 years ago

7 0

Answer:

X+(X+1)+X+2)=30

Step-by-step explanation:

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Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

$f(x) = 2$ is a valid solution.

Want something more fun? Why not a parabola? $f(x)= ax^2+bx+c$ .

At this point you have three parameters to play with, and from the fact that $f(0)=2$ we can already fix one of them, in particular $c=2$ . At this point I would recommend picking an easy value for one of the two, let's say $a= 1$ (or even $a=-1$ , it will just flip everything upside down) and find out b accordingly: $f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1$

Our function becomes

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Notice that it works even by switching sign in the first two terms: $f(x) = -x^2+x+2$

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: $f(x) = A cos (kx)$

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Or how about a sine wave that oscillates around 2? with a similar reasoning you get

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