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alexandr402 [8]

2 years ago

12

Three consecutive integers have a sum of 30. Which equation can be used to find x, the value of the smallest of the three number

s? (x + 1) + (x + 2) = 30 x + (x + 1) + (x + 2) = 30 x (x + 1) (x + 2) = 30 3 x (x + 1) (x + 2) = 30

1 answer:

castortr0y [4]2 years ago

7 0

Answer:

X+(X+1)+X+2)=30

Step-by-step explanation:

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M>5=m>4
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by substituting
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True or false:x/3 is equivalent to 1/3x.explain your reasoning.

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3 years ago

Read 2 more answers

Sedaia [141]

Answer:

$x = 18$

Step-by-step explanation:

Given

$\frac{x}{6} - 7 = -4$

Required

Solve for x

$\frac{x}{6} - 7 = -4$

Add 7 to both sides

$\frac{x}{6} - 7+7 = -4+7$

$\frac{x}{6} = -4+7$

$\frac{x}{6} = 3$

Multiply through by 6

$6 * \frac{x}{6} = 3 * 6$

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3 years ago

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3 years ago

What's the answer to this 94<-2(1+6b)

tigry1 [53]

Answer:

-8 > b

Step-by-step explanation:

94<-2(1+6b)

Distribute

94<-2-12b

Add 2 to each side

94+2<-2-12b +2

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Divide each side by -12, remembering to flip the inequality since we divide by a negative

96/-12 > -12b/-12

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