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4 years ago

11

Marna is playing game where you score -5 points each time you guess the correct answer. The goal is to get the lowest score . To

win the game Marna must have a score less than -80 points. How many correct answer thet Marna need to win the game

1 answer:

umka2103 [35]4 years ago

5 0

MORE THAN 16 CORRECT ANSWES

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The measure of the supplement of an angle is 20° more than three times the measure of the original angle. find the measures of t

viva [34]

If the original angle is x degrees then its supplement is 180 - x degrees.

we have the equation:-

180 - x = 3x + 20

160 = 4x

x = 40

The original angle is 40 degrees and its supplement is 140 degrees

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nikitadnepr [17]

The answer for question 47 is A

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3 years ago

the gross income is $215 per week the deductions are $15.16,$29.33,2%,1%,and 3% what is the net income

Naddik [55]

State tax = 2% of $215 = 0.02 x $215 = $4.30
city tax = 1% of $215 = 0.01 x $215 = $2.15
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Net income = $215 - $57.39 = $157.61

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3 years ago

Learn with an example v Luke counted the number of silver beads on each bracelet at Lexington Jewelry, the store where he works.

Juli2301 [7.4K]

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3 years ago

Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar

klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

$\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}$

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

$CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack$

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

$CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack$

Where (from tables):

$Z_{0.99}=2.33$

Finally, the interval at 98% confidence level is:

$CI(\mu)=\lbrack28.94,31.06\rbrack$

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1 year ago