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3 years ago

7

A leaky faucet is losing water and is filling a 8-gallon bucket every 25 hours.At this rate,how many gallons of water will the f

aucet leak in 13 hours?

1 answer:

Angelina_Jolie [31]3 years ago

6 0

The rate of 8 gallons every 25 hours means that the faucet fills $\frac{8}{25}$ gallons every hour.

Multiply the unit rate for the number of hours you're interested in to find

$\dfrac{8}{25}\cdot 13 = \dfrac{104}{25}$

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Solve log 4x + log 13 = 0. Round to the nearest thousandth if necessary. a.0.019 b. 52 c.3.25 d. 0.311 Mathematics

kumpel [21]

Log4 + logX + log13 = 0
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logX = -1.716
x= 10^[-1.716]
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3 years ago

What is the horizontal asymptote of the function f(x)= -2x/x+1

daser333 [38]

<u>Answer:</u>

-2

<u>Step-by-step explanation:</u>

We have been given a function f(x)=\frac{-2x}{x+1} and we are asked to find the horizontal asymptote of our given function.

Recalling the rules for a horizontal asymptote:

1. If the numerator and denominator have equal degree, the horizontal asymptote will be the ratio of the leading coefficients.

2. If the polynomial of denominator has larger degree than the numerator, then the horizontal asymptote will be the x-axis or y=0.

3. If the polynomial of numerator has larger degree than denominator, then the function has no horizontal asymptote.

Here, the numerator and denominator are of the same degree. So the horizontal asymptote will be the ratio of the coefficients.

Horizontal asymptote = $-\frac{2}{1}$ = -2

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First anserw gets brainest 8th grade, root squared question

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Answer:

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