Ask question

Ask question

All categories

3 years ago

5

If hoan was asked to drow a right angke how miny right agnkes are in a right angle

1 answer:

krek1111 [17]3 years ago

4 0

I might not understand this correctly because of the misspellings, but if you draw a right angle. There is only 1 right angle... in a right angle.

You might be interested in

The first three terms of a sequence are given. Round to the nearest thousandth (if

dimulka [17.4K]

Step-by-step explanation:

25,375,000

please give me brainliest for no reason because you are a generous and kind person!!!!!

8 0

3 years ago

5<br> The slope of EF is<br> Which segments are perpendicular to EF?<br> Select each correct answer.

Anvisha [2.4K]

Answer:

the first two answers are perpendicular

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=10%5Csqrt12%20%2B4%5Csqrt%7B192" id="TexFormula1" title="10\sqrt12 +4\sqrt{192" alt="10\sqrt12

crimeas [40]

Here's the answer :)

5 0

3 years ago

(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0

Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

$P(A)+P(B)+P(A\cap B)=P(A\cup B)$

We know that

Maximum value of $P(A\cup B)$ =1 and minimum value of $P(A\cup B)$ =0

$0\leq P(A\cup B )\leq 1$

$0\leq P(A)+P(B)-P(A\cap B)\leq 1$

$0\leq 0.4+0.7-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)$

$P(A\cap B)\leq 1.1$

It is not possible that $P(A\cap B)$ is equal to 1.1

$1.1-P(A\cap B)\leq 1$

$-P(A\cap B)\leq 1-1.1=-0.1$

Multiply by (-1) on both sides

$P(A\cap B)\geq 0.1$

Again, $P(A\cup B)\geq P(B)$

$0.4+0.7-P(A\cap B)\geq 0.7$

$1.1-P(A\cap B)\geq 0.7$

$-P(A\cap B)\geq -1.1+0.7=-0.4$

Multiply by (-1) on both sides

$P(A\cap B)\leq 0.4$

Hence, $0.1\leq P(A\cap B)\leq 0.4$

3 0

3 years ago

What quadrants is the points (2,-3)?

zheka24 [161]

Answer:

Quadrant 4

there are four quantdrants, A is on the fourth one

4 0

2 years ago