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Dmitry_Shevchenko [17]
3 years ago
5

A plumber charges $50 for a service call plus $80 per hour. If she spends no longer than 8 hours a day at any one site, find a l

inear function that represents her total daily charges C (in dollars) as a function of time t (in hours) spent at any one given location.
Mathematics
1 answer:
Paha777 [63]3 years ago
3 0

Answer:

C(t)=80t+50, \text{ for }t\leq 8.

Step-by-step explanation:

Let C represent total daily charges in dollars and t represent time in hours.

We have been given that a plumber charges $50 for a service call plus $80 per hour.  

The amount charged for t hours would be 80t.

The total amount charged for t hours would be C(t)=80t+50.

We are also told that plumber spends no longer than 8 hours a day at any one site, this means that time t have a restriction as:

t\leq 8

Therefore, our required cost function would be C(t)=80t+50, \text{ for }t\leq 8.

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Leslie bought 6 watermelons the weighed 3 5/8 pounds each. How much did weigh all together?
VashaNatasha [74]

Answer:

The answer is 105/4

Step-by-step explanation:

6 \times  \frac{35}{8}  =  \frac{3 \times 35}{4}  =  \frac{105}{4}

6 0
3 years ago
Read 2 more answers
My Homework Mr Thompson please help!!
Nady [450]

Answers:

  1. C) Factored form
  2. C) Standard form
  3. D) The y intercept is -8
  4. B) Two solutions: x = -5 or x = 5
  5. B) Apply square root to both sides

=========================================

Explanations:

  • For problems 1 and 2, there's not much to say other than you'll just have to memorize those terms. Standard form is ax^2+bx+c in general. The exponents count down 2,1,0. Factored form is where we have two or more factors multiplying with each other. Think of something like 21 = 7*3 showing that 7 and 3 are factors of 21.
  • For problem 3, the y intercept is the last value. It's the constant value. Plug in x = 0 and you'll get y = -8 as a result. The y intercept always occurs when x = 0.
  • In problem 4, we apply the square root to both sides to get x = -5 or x = 5. The plus or minus is needed. This is because (-5)^2 = 25.
  • In problem 5, we apply the square root to both sides to undo the squaring operation.
4 0
3 years ago
A publisher requires 2⁄3 of a page of advertisements for every 5 pages in a magazine. If a magazine has 98 pages, to the nearest
rjkz [21]

Let x be the number of pages of advertisements.

Write a proportion from the table:

\dfrac{2}{3} of a page of advertisment - 5 pages in a magazine

x pages of advertisment - 98 pages in a magazine,

then

\dfrac{\dfrac{2}{3}}{x}=\dfrac{5}{98}.

Find x:

x=\dfrac{\dfrac{2}{3}\cdot 98}{5}=\dfrac{196}{15}=13\dfrac{1}{13}.

Answer: 13 whole pages and \dfrac{1}{13} of 14th page are advertisments, so 14 pages contain advertisments.

3 0
3 years ago
-3-2(2x-3) simplified
ddd [48]
First Distribute, then subtract and you’ll get -4x+3
6 0
3 years ago
Can someone write down the answers pls!!!!!!!!!!
snow_lady [41]

Step-by-step explanation:

6b x>=1

6c y>7

7a x>3

7b -2<=2x<6

-1<=x<3

answer:-1,0,1,2,3

7 0
3 years ago
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