Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or
ft
=
ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
=
ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k(
)
k = 18
Work done (W) to stretch the spring by
ft will be
W = 
= 
= ![18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0](https://tex.z-dn.net/?f=18%5B%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%5D%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D_0)
= 9(
)²
= 7.56 lb-ft
Answer:
18cm if that's what you were asking for
Step-by-step explanation:
For
y=a(x-h)^2+k
the axis of symmetry is x=h
so
y=2/3(x-2)^2-5
the axis of symmetry is x=2
answer is C
Answer:21 cm
Step-by-step explanation: The circle's circumference is 84 cm. 84 / 4 = 21. Therefore the length of the arc XY is 21 cm.
Answer:
C.
Step-by-step explanation: