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s344n2d4d5 [400]
3 years ago
14

Which equation represents a proportional relationship?

Mathematics
2 answers:
umka2103 [35]3 years ago
8 0

As written here, both choices B and C represent proportional relationships:

... B. y = 12x

... C. y = 3x

_____

One key to a proportional relationship is that when one variable is zero, so is the other. This will not be the case for selections A and D.

Setler [38]3 years ago
7 0

Answer:

y=12x

y=3x

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope of the line m, and the line passes trough the origin

so

case A) y=-3x+2  

Is a linear equation but does not passes trough the origin

case B) y=12x

Is a linear equation and passes trough the origin-----> represent a proportional relationship

case C) y=3x  

Is a linear equation and passes trough the origin-----> represent a proportional relationship

case D) y=2(x+13)

Is a linear equation but does not passes trough the origin

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sume of angles of a triangel greater than 180 degrees when teh triange is so large that it extends to cosmological scales
Vesna [10]

In hyperbolic geometry, the angle sum of a triangle is always less than 180 degrees.

A lune is a wedge of a sphere with angle θ, represented by L(θ) in the proof.

α, β, and γ are the three angles of the triangle.

4πr²+4area[αβγ]=2L(α)+2L(β)+2L(γ)

2(2πr²+2area[αβγ])=2(L(α)+L(β)+L(γ))

2πr²+2area[αβγ]=L(α)+L(β)+L(γ)

At this point, we need to use a theorem that states that a lune whose corner angle is θ radians has an area of 2θr².

2πr²+2area[αβγ]=2αr²+2βr²+2γr²

2πr²+2area[αβγ]=2r²(α+β+γ)

π+area[αβγ]r²=α+β+γ

At this point, it is clear that the sum of the angles is equal to π plus the area[αβγ]r² (which cannot be zero).

To learn more about triangles and geometry,

brainly.com/question/2773823

#SPJ4

5 0
10 months ago
A professional baseball diamond is a square. The distance from base to base is 90 ft. To the nearest foot, how far does a catche
mamaluj [8]

BSE is square.

Let side be s

  • s=90ft

Diagonal be d

\\ \tt\longmapsto s=\dfrac{d}{\sqrt{2}}

\\ \tt\longmapsto d=s\sqrt{2}

\\ \tt\longmapsto d=90\sqrt{2}

\\ \tt\longmapsto d=127ft

3 0
2 years ago
Read 2 more answers
Help pretty please .w.
sineoko [7]
I don’t know what that is it’s probably 9999999
4 0
3 years ago
Read 2 more answers
In a triangle ABC, measure of angle B is 90 degrees. AB is 3x-2 units and BC is x+3. If the area of the triangle is 17 sq cm, fo
Scorpion4ik [409]

Answer:

x=\frac{8}{3}\ cm

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

A=\frac{1}{2}(AB)(BC)

we have

A=17\ cm^2

AB=(3x-2)\ cm

BC=(x+3)\ cm

substitute the values

17=\frac{1}{2}(3x-2)(x+3)

34=(3x-2)(x+3)

34=3x^2+9x-2x-6

3x^2+7x-6-34=0

3x^2+7x-40=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

3x^2+7x-40=0

so

a=3\\b=7\\c=-40

substitute in the formula

x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}

x=\frac{-7(+/-)\sqrt{529}} {6}

x=\frac{-7(+/-)23} {6}

x=\frac{-7(+)23} {6}=\frac{16}{6}=\frac{8}{3}

x=\frac{-7(-)23} {6}=-5

therefore

The solution is

x=\frac{8}{3}\ cm

6 0
2 years ago
If a 100.8 kg cement bag had 20.35 kg removed from it, what is the new weight of the bag?
Snowcat [4.5K]
Just subtract 20.35 from 100.8
100.8 \: kg - 20.35 \: kg = 80.45 \: kg

if your bag weighs 100.8 kg and you scoop out 20.35 kg then weigh your bag it will be 80.45 bc u took out 20.35 kg of the cement to use. hope that explains it
8 0
3 years ago
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