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3 years ago

Which equation represents a proportional relationship?

Mathematics

2 answers:

umka2103 [35]3 years ago

8 0

As written here, both choices B and C represent proportional relationships:

... B. y = 12x

... C. y = 3x

_____

One key to a proportional relationship is that when one variable is zero, so is the other. This will not be the case for selections A and D.

Setler [38]3 years ago

7 0

Answer:

$y=12x$

$y=3x$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope of the line m, and the line passes trough the origin

case A) $y=-3x+2$

Is a linear equation but does not passes trough the origin

case B) $y=12x$

Is a linear equation and passes trough the origin-----> represent a proportional relationship

case C) $y=3x$

Is a linear equation and passes trough the origin-----> represent a proportional relationship

case D) $y=2(x+13)$

Is a linear equation but does not passes trough the origin

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Vesna [10]

In hyperbolic geometry, the angle sum of a triangle is always less than 180 degrees.

A lune is a wedge of a sphere with angle θ, represented by L(θ) in the proof.

α, β, and γ are the three angles of the triangle.

4πr²+4area[αβγ]=2L(α)+2L(β)+2L(γ)

2(2πr²+2area[αβγ])=2(L(α)+L(β)+L(γ))

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At this point, we need to use a theorem that states that a lune whose corner angle is θ radians has an area of 2θr².

2πr²+2area[αβγ]=2αr²+2βr²+2γr²

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At this point, it is clear that the sum of the angles is equal to π plus the area[αβγ]r² (which cannot be zero).

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10 months ago

A professional baseball diamond is a square. The distance from base to base is 90 ft. To the nearest foot, how far does a catche

mamaluj [8]

BSE is square.

Let side be s

s=90ft

Diagonal be d

$\\ \tt\longmapsto s=\dfrac{d}{\sqrt{2}}$

$\\ \tt\longmapsto d=s\sqrt{2}$

$\\ \tt\longmapsto d=90\sqrt{2}$

$\\ \tt\longmapsto d=127ft$

3 0

2 years ago

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sineoko [7]

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3 years ago

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In a triangle ABC, measure of angle B is 90 degrees. AB is 3x-2 units and BC is x+3. If the area of the triangle is 17 sq cm, fo

Scorpion4ik [409]

Answer:

$x=\frac{8}{3}\ cm$

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

$A=\frac{1}{2}(AB)(BC)$

we have

$A=17\ cm^2$

$AB=(3x-2)\ cm$

$BC=(x+3)\ cm$

substitute the values

$17=\frac{1}{2}(3x-2)(x+3)$

$34=(3x-2)(x+3)$

$34=3x^2+9x-2x-6$

$3x^2+7x-6-34=0$

$3x^2+7x-40=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2+7x-40=0$

$a=3\\b=7\\c=-40$

substitute in the formula

$x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}$

$x=\frac{-7(+/-)\sqrt{529}} {6}$

$x=\frac{-7(+/-)23} {6}$

$x=\frac{-7(+)23} {6}=\frac{16}{6}=\frac{8}{3}$

$x=\frac{-7(-)23} {6}=-5$

therefore

The solution is

$x=\frac{8}{3}\ cm$

6 0

2 years ago

If a 100.8 kg cement bag had 20.35 kg removed from it, what is the new weight of the bag?

Snowcat [4.5K]

Just subtract 20.35 from 100.8
$100.8 \: kg - 20.35 \: kg = 80.45 \: kg$

if your bag weighs 100.8 kg and you scoop out 20.35 kg then weigh your bag it will be 80.45 bc u took out 20.35 kg of the cement to use. hope that explains it

8 0

3 years ago