Answer:
See explaination
Explanation:
def readFileFirstLast(filename):
# doc string
''' Function accept the filename and opens the fle
and reads all lines and strips new line character and
stores first and last in a string and return that string'''
#eception handle if file not found
try:
#opening the file
f = open(filename)
#reading the first line and striping the ne line
string = f.readline().strip()
#iterating until last line
for line in f:
pass
#concate the last line after strip the new line character to the string
string = string + " " + line.strip()
#return the string
return string
except:
#if file not found
return "File not found"
#taking the file name from user
filename = input("Enter a file name: ")
#printing the doc string in function
print("\ndoc_sting: \n"+ readFileFirstLast.__doc__+"\n")
#printing the returned string by calling the readFileFirstLast()
print("output string :")
print(readFileFirstLast(filename))
Answer:
The answer to this question is given below in this explanation section.
Explanation:
A smart Art graphic is a visual representation of your information and ideas.you create one by choosing a layout this fits your message.Some layouts specific kind of information,while other simply enhance the appearance of a bulleted list.
You can create a smart graphic in excel power point,word,or in an email message in outlook.The smart button is one the insert tab and developing on your screen size,may look like.
Other office program do not allow for smart art art graphic creation,but you can copy and paste smart graphics as image into those programs.As part of this process,when you are prompted to choose a type such as process hierarchy,or relationship.A type is similar to a category of smart art graphic,and each type contains several different layouts.
Because you can quickly and easily switch layouts,try different layouts until you find the one that best illustrate your message.
Answer:
Explanation:
The following code is written in Python. It asks the user for an input. Then cleans the input using regex to remove all commas, whitespace, and apostrophes as well as making it all lowercase. Then it reverses the phrase and saves it to a variable called reverse. Finally, it compares the two versions of the phrase, if they are equal it prints out that it is a palindrome, otherwise it prints that it is not a palindrome. The test case output can be seen in the attached picture below.
import re
phrase = input("Enter word or phrase: ")
phrase = re.sub("[,'\s]", '', phrase).lower()
reverse = phrase[::-1]
if phrase == reverse:
print("This word/phrase is a palindrome")
else:
print("This word/phrase is NOT a palindrome")
Answer:
/*
I don't know what language you're using, so I'll write it in javascript which is usually legible enough.
*/
console.log(buildSequence(30));
function buildSequence(maxVal){
maxVal = Math.abs(maxVal);
var n, list = [];
for(n = 1; n < maxVal; n++){
/*
to check for odd numbers, we only need to know if the last bit
is a 1 or 0:
*/
if(n & 1){ // <-- note the binary &, as opposed to the logical &&
list[list.length] = n;
}else{
list[list.length] = -n;
}
}
return list.implode(',');
}
