Members of an Agile development team often agrees on what tasks to work on and they do it together. The one possible solution to this challenge is to Have the database developer train the rest of the team so there are fewer handoffs.
Agile development team often works together as a team. They as team discuss the task yo take, when it will take place etc.
This team is all about communication, teamwork, problem-solving etc.
Conclusively, A task should be completed by one member on the team, but the team may choose to pair up when doing the work.
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See full question below:
Your agile team only has one person who knows how to develop database software. So the other developers finish their tasks and then wait for their work to be Integrated into the database. This creates a pile of backed up work for the database developer. But it also means that the other developers must either wait or add to the growing pile of database work. What's one possible solution to this challenge?
Select an answer:
Have the database developer train the rest of the team so there are fewer handoffs.
Have the software developers split their time between other teams so they're not as productive
Encourage the database developer to work overtime to catch up with their work.
Create a large batch of work so the database developer can focus on finishing
Answer:
Quite simply, when you double your ISO speed, you are doubling the brightness of the photo. So, a photo at ISO 400 will be twice brighter than ISO 200, which will be twice brighter than ISO 100.
Explanation:
ISO most often starts at the value of ISO 100. This is the lowest, darkest setting, also called the base ISO. The next full stop, ISO 200, is twice as bright, and ISO 400 is twice as bright than that. Thus, there are two stops between ISO 100 and 400, four stops between 100 and 1600, and so on.
The option that best explains the game is that a game can have multiple instances using the same class.
<h3>Can a class have multiple instances?</h3>
A game is one that can always create multiple instances of a class. This is known to be the reason that classes are made.
Conclusively, each object often has its own specific inner variables and they do not have only if they are static but games of multiple instances is the reason why there is only one class with the new characters.
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Answer:
- def check_subset(l1, l2):
- status = False
- count = 0
- if(len(l1) > len(l2)):
- for x in l2:
- for y in l1:
- if x == y:
- count += 1
-
- if(count == len(l2)):
- return True
- else:
- return False
-
- else:
- for x in l1:
- for y in l2:
- if x==y:
- count += 1
-
- if(count == len(l1)):
- return True
- else:
- return False
-
- print(check_subset([1,4,6], [1,2,3,4,5,6]))
- print(check_subset([2,5,7,9,8], [7,8]))
- print(check_subset([1, 5, 7], [1,4,6,78,12]))
Explanation:
The key idea of this solution is to create a count variable to track the number of the elements in a shorter list whose value can be found in another longer list.
Firstly, we need to check which list is shorter (Line 4). If the list 2 is shorter, we need to traverse through the list 2 in an outer loop (Line 5) and then create another inner loop to traverse through the longer list 1 (Line 6). If the current x value from list 2 is matched any value in list 1, increment the count variable by 1. After finishing the outer loop and inner loop, we shall be able to get the total count of elements in list 2 which can also be found in list 1. If the count is equal to the length of list 2, it means all elements in the list 2 are found in the list 1 and therefore it is a subset of list 1 and return true (Line 10-11) otherwise return false.
The similar process is applied to the situation where the list 1 is shorter than list 2 (Line 15-24)
If we test our function using three pairs of input lists (Line 26-28), we shall get the output as follows:
True
True
False
A<span> DHCPOffer packet is sent to the client.</span>
