Answer:
a) D = 4.88 * 10^(-14) m^2 / s
b) <em>t </em>= 1.1 hr
Solution:
a) Magnesium in Aluminum diffusion:
D = Do * exp(-Qd / RT)
= (1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15)
= 4.88 * 10^(-14) m^2 / s
D = 4.88 * 10^(-14) m^2 / s
b) The composition remains same at say the distance Xo:
(Cx - Co) / (Cs - Co) = Constant
Xo^2 / D_{550} * <em>t </em>= Xo^2 / D_{450} * 15
D_{550} * <em>t </em>= D_{450} * 15
(1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15) * <em>t</em>
(4.88 * 10^(-14) m^2 / s) * 15
by, solving for <em>t </em>we get:
<em>t </em>= 1.1 hr
So, the time required is 1.1 hr.
Answer:
The function is as follows:
import math
def func(x,y,z):
print(math.pow(x, z))
print(math.pow(x,math.pow(y, z)))
print(math.fabs(y))
print(math.sqrt(math.pow(x*y,z)))
Explanation:
This imports the math library
import math
This defines the function
def func(x,y,z):
Print the stated outputs as it is in the question
<em> print(math.pow(x, z)) ---> x to power x</em>
<em> print(math.pow(x,math.pow(y, z))) ---- x to power of y of z</em>
<em> print(math.fabs(y)) ---- absolute of y</em>
<em> print(math.sqrt(math.pow(x*y,z))) --- square root of xy power x</em>
<em />
<span>If I wanted to share files only within my organization and limit my employees from sharing information with external people, what type of network should I set up in my office?
Extranet<====
Internet
Peer-to-Point
Intranet
hopes this helps
</span>
