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3 years ago

How do I round 47,283 to the nearest 100,000

Mathematics

1 answer:

rosijanka [135]3 years ago

7 0

The answer is zero.

Explanation:

The 4 is in the ten-thousands place.

Write the number 47,283 with an additional zero in the 100,000 place.

047,283

To round to the nearest 100,000, all digits to the right of the 100,000 place become zero. That means that the digits 47283 all become zero. Since 4 is less than 5, the digit to its left is not raised by 1, so the 100,000 place digit remains zero, and you end up with 000,000, which is simply 0.

Answer: 0

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There are 280 pieces of fruit in a fruit salad. There are twice as many raspberries as blueberries, three times as many grapes a

dedylja [7]

Answer:

64 cherries

Step-by-step explanation:

Given that

There are 280 pieces of fruit in a fruit salad

There are twice as many raspberries as blueberries,

three times as many grapes as cherries,

and four times as many cherries as raspberries

We need to find out the number of cherries in the fruit salad

So,

Let us assume the blueberries be x

So, the raspberries be 2x

Cherries be 8x

And, grapes be 24x

Now

x + 2x + 24x + 8x = 280

35x = 280

x = 8

hence, the No of cherries in the salad

= 8 x

= 8(8)

= 64 cherries

5 0

3 years ago

The slope that goes through the points (3,-4) and (-2,6)

kicyunya [14]

Answer:

slope = -2

Step-by-step explanation:

Slope = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$= \frac{6-[-4]}{-2-3}\\\\= \frac{6+4}{-2-3}\\\\= \frac{10}{-5}\\\\= -2$

7 0

3 years ago

Eighteen less than three times a number is twice the number. Write and solve

goblinko [34]

Answer:

The number is 18

Step-by-step explanation:

You can write an equation to represent this. Let x represent the unknown number.

3x - 18 = 2x

Move 2x to the left side. Remember, "change the side, change the sign." Add 0 as a placeholder to the right of the equals sign.

3x - 2x - 18 = 0

Simplify like terms.

x - 18 = 0

Move -18 to the right of the equals sign.

x = 18

Now that we know x = 18, we can substitute it into the problem.

"Eighteen less than three times 18 is two times 18."

18 x 3 = 54

54 - 18 = 36

36 is, in fact, two times 18. We can check this by dividing 36 by 2.

36 ÷ 2 = 18

8 0

3 years ago

For the following telescoping series, find a formula for the nth term of the sequence of partial sums {Sn}. Then evaluate limn→[

Ivenika [448]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

Given value:

$1) \sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2}\\\\2) \sum ^{\infty}_{k = 1} \frac{1}{(k+6)(k+7)}$

Solve point 1 that is $\sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2}\\\\$ :

when,

$k= 1 \to s_1 = \frac{1}{1+1} - \frac{1}{1+2}\\\\$

$= \frac{1}{2} - \frac{1}{3}\\\\$

$k= 2 \to s_2 = \frac{1}{2+1} - \frac{1}{2+2}\\\\$

$= \frac{1}{3} - \frac{1}{4}\\\\$

$k= 3 \to s_3 = \frac{1}{3+1} - \frac{1}{3+2}\\\\$

$= \frac{1}{4} - \frac{1}{5}\\\\$

$k= n^ \to s_n = \frac{1}{n+1} - \frac{1}{n+2}\\\\$

Calculate the sum $(S=s_1+s_2+s_3+......+s_n)$

$S=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+.....\frac{1}{n+1}-\frac{1}{n+2}\\\\$

$=\frac{1}{2}-\frac{1}{5}+\frac{1}{n+1}-\frac{1}{n+2}\\\\$

When $s_n \ \ dt_{n \to 0}$

$=\frac{1}{2}-\frac{1}{5}+\frac{1}{0+1}-\frac{1}{0+2}\\\\=\frac{1}{2}-\frac{1}{5}+\frac{1}{1}-\frac{1}{2}\\\\= 1 -\frac{1}{5}\\\\= \frac{5-1}{5}\\\\= \frac{4}{5}\\\\$

$\boxed{\text{In point 1:} \sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2} =\frac{4}{5}}$

In point 2: $\sum ^{\infty}_{k = 1} \frac{1}{(k+6)(k+7)}$

when,

$k= 1 \to s_1 = \frac{1}{(1+6)(1+7)}\\\\$

$= \frac{1}{7 \times 8}\\\\= \frac{1}{56}$

$k= 2 \to s_1 = \frac{1}{(2+6)(2+7)}\\\\$

$= \frac{1}{8 \times 9}\\\\= \frac{1}{72}$

$k= 3 \to s_1 = \frac{1}{(3+6)(3+7)}\\\\$

$= \frac{1}{9 \times 10} \\\\ = \frac{1}{90}\\\\$

$k= n^ \to s_n = \frac{1}{(n+6)(n+7)}\\\\$

calculate the sum: $S= s_1+s_2+s_3+s_n\\$

$S= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{(n+6)(n+7)}\\\\$

when $s_n \ \ dt_{n \to 0}$

$S= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{(0+6)(0+7)}\\\\= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{6 \times 7}\\\\= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{42}\\\\=\frac{45+35+28+60}{2520}\\\\=\frac{168}{2520}\\\\=0.066$

$\boxed{\text{In point 2:} \sum ^{\infty}_{k = 1} \frac{1}{(n+6)(n+7)} = 0.066}$

8 0

3 years ago

If x = -4, calculate 2x squared - 5

Varvara68 [4.7K]

You just substitute the value of x in the given equation:

f(x) = 2x^2 - 5

f(-4) = 2 (-4)^2 -5 = 27

f(x) : a name given to the equation
f(-4): refer to the equation when the value of the independent variable x has the value between the brackets.

5 0

3 years ago