All categories

3 years ago

How do I round 47,283 to the nearest 100,000

Mathematics

1 answer:

rosijanka [135]3 years ago

7 0

The answer is zero.

Explanation:

The 4 is in the ten-thousands place.

Write the number 47,283 with an additional zero in the 100,000 place.

047,283

To round to the nearest 100,000, all digits to the right of the 100,000 place become zero. That means that the digits 47283 all become zero. Since 4 is less than 5, the digit to its left is not raised by 1, so the 100,000 place digit remains zero, and you end up with 000,000, which is simply 0.

Answer: 0

You might be interested in

Comparing Decimals

LenKa [72]

Answer:

.67<0.8 """""""""""""""""""

7 0

3 years ago

Please answer this question correctly and i'll mark you as brainlilest! Thank you.

raketka [301]

Answer:

$\frac{ {7}^{4} ( - 2) {}^{4} {11}^{3} 6}{7 {}^{3} {2}^{2} {6}^{2} 11 {}^{2} } = \frac{7 \times {2}^{2} \times 11}{6} = \frac{308}{6} = \frac{154}{3} \\ \\ \frac{ {7}^{0} {12}^{0} {17}^{0} }{ {57}^{0} + ( {42}^{0} \times ( {13}^{0} ))} = \frac{1}{1 + 1} = \frac{ 1}{2}$

4 0

3 years ago

Is (5,15) a solution of the equation y= 3x? (plz answer asap)

sashaice [31]

Answer:

Yes

Step-by-step explanation:

15 = 3(5)

15 = 15

You plug in the point

6 0

3 years ago

Prove that sec^2x-cosec^2x=tan^2x-cot^2x

Agata [3.3K]

Use the identities sec^2(x) = tan^2(x) + 1 and cosec^2(x) = 1 + cot^2 (x), both are derived from the pythagorean identity of 1 = sin^2 (x) + cos^2 (x) by dividing through by either sin2 or cos2 .

6 0

4 years ago

Read 2 more answers

)Suppose is a real number with 0 < < 4 . Set = sin( − ), = cos( + ), = sin( − ), and = cos(2 − ). Arrange the values , , ,

jok3333 [9.3K]

Answer:

b < c < a < d

Step-by-step explanation:

P.S - The exact question is -

Given - Suppose x is a real number with 0 < x < $\frac{\pi }{4}$ . Set a = sin( $\pi$ - x) ,

b = cos( $\pi$ + x) , c = sin( x - $\pi$ ) , d = cos(2 $\pi$ - x)

To find - Arrange the values of a, b, c, d in increasing order , and explain

how you determined their order.

Proof -

Firstly draw a unit circle where you indicate the following

A = ( cos(x), sin(x) )

B = ( cos( $\pi$ - x) , sin ( $\pi$ - x) )

C = ( cos( $\pi$ + x), sin ( $\pi$ + x) )

D = ( cos (2 $\pi$ - x) , sin (2 $\pi$ - x) )

As we have given that 0 < x < $\frac{\pi }{4}$

⇒sin (x) and cos(x) are positive and sin(x) < cos(x)

The figure is as follows :

Now

By seeing point B , we can say that

sin ( $\pi$ - x) = sin (x) = a

By seeing point C , we can say that

cos( $\pi$ + x) = -cos (x) = b

By seeing point C , we can say that

sin( x - $\pi$ ) = -sin(x) = c

By seeing point D , we can say that

cos(2 $\pi$ - x) = cos(x) = d

As sin(x) < cos(x) ⇒ a < d

-sin(x) > -cos(x) ⇒ c > b ⇒ b< c

and as we know that -sin(x) < sin(x) ⇒ c < a

∴ we get

b < c < a < d

3 0

3 years ago