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pshichka [43]
2 years ago
11

I need help with this question.

Mathematics
1 answer:
klio [65]2 years ago
5 0
The answer is E your welcome
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I need you to take 18% off the the $80.00 total charge. that should be?
Anastasy [175]
That would be 14.4 :)
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2 years ago
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......is an example of
Stolb23 [73]

Answer:

The answer would be 'D'.

Step-by-step explanation:

An expression does NOT have an equal sign while a formula does. A variable is some letter symbol that you are solving for, but a constant would be a number such as 2 or 4 that could be added, multiplied, subtracted, or divided in an equation. 

I hope this helps!

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3 years ago
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What should I buy? A study conducted by a research group in a recent year reported that of cell phone owners used their phones i
Llana [10]

Answer:

The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.

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Step-by-step explanation:

<em>The question is incomplete:</em>

<em>What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions? </em>

We can model this as a binomial random variable, with p=0.57 and n=14.

P(x=k)=\dbinom{n}{k} p^{k}q^{n-k}

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:

P(x\geq7)=\sum_{k=7}^{14}P(x=k)\\\\\\

P(x=7)=\dbinom{14}{7} p^{7}q^{7}=3432*0.0195*0.0027=0.1824\\\\\\P(x=8) = \dbinom{14}{8} p^{8}q^{6}=3003*0.0111*0.0063=0.2115\\\\\\P(x=9) = \dbinom{14}{9} p^{9}q^{5}=2002*0.0064*0.0147=0.1869\\\\\\P(x=10) = \dbinom{14}{10} p^{10}q^{4}=1001*0.0036*0.0342=0.1239\\\\\\P(x=11) = \dbinom{14}{11} p^{11}q^{3}=364*0.0021*0.0795=0.0597\\\\\\P(x=12) = \dbinom{14}{12} p^{12}q^{2}=91*0.0012*0.1849=0.0198\\\\\\P(x=13) = \dbinom{14}{13} p^{13}q^{1}=14*0.0007*0.43=0.004\\\\\\

P(x=14) = \dbinom{14}{14} p^{14}q^{0}=1*0.0004*1=0.0004\\\\\\

P(x\geq7)=0.1824+0.2115+0.1869+0.1239+0.0597+0.0198+0.004+0.0004\\\\P(x\geq7)=0.7886

7 0
3 years ago
In the past month, Amy rented 7 video games and 4 DVDs. The rental price for each video game was $3.30. The rental price for eac
Lera25 [3.4K]

Answer:

$39.90

Step-by-step explanation:

if each video game cost $3.30, and she rented 7, then you multiply $3.30 by 7, to get $21.10, and if each DVD was $4.20, and she rented 4, then its $4.20x4= $16.80

after that you just add the two total costs together, which is $23.10+$16.80=$39.90

8 0
3 years ago
What type of solution is x^2 + 10x + 25 = 0
MaRussiya [10]
Hello.

There is only one solutin for <span> x^2 + 10x + 25 = 0

You can tell because it ends with a 0.

Have a nice day</span>
5 0
3 years ago
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