Answer:
(3,2)
Step-by-step explanation:
The coordinates of the point P on the given graph is (-1,5).
So, when we translate point P on the graph by 4 units to the right its x-coordinate will change to (- 1 + 4) = 3.
Again, when we translate point P on the graph by 3 units down then its y-coordinate will change to (5 - 3) = 2.
Therefore, the new coordinates of the point P will be (3,2) (Answer)
( f + g ) (x) = –2x + 6
( f – g ) (x) = 8x – 2
( f × g ) (x) = –15x2 + 2x + 8
<span>\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}<span><span>(<span><span>g</span><span>f</span><span></span></span>)</span>(x)=<span><span><span>4−5x</span></span><span><span>3x+2</span></span><span></span></span></span></span>
The mode of a set of numbers is the number that occurs the most.
The numbers in this set are as follows,
26, 17, 9, 12, 18, 21, 9, 14, 18, 23, 15, 7, 20, 18, 17, and 12
26 I
17 II
9 II
12 II
18 III
21 I
14 I
23 I
15 I
7 I
20 I
The number that appears the most is 18!
So the mode of the set of numbers is 18!
Answer:
4Joules
Step-by-step explanation:
According to Hooke's law which states that extension of an elastic material is directly proportional to the applied force provide that the elastic limit is not exceeded. Mathematically,
F = ke where
F is the applied force
K is the elastic constant
e is the extension
If a spring exerts a force of 6 N when stretched 3 m beyond its natural length, its elastic constant 'k'
can be gotten using k = f/e where
F = 6N, e = 3m
K = 6N/3m
K = 2N/m
Work done on an elastic string is calculated using 1/2ke².
If the spring is stretched 2 m beyond its natural length, the work done on the spring will be;
1/2× 2× (2)²
= 4Joules
