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3 years ago

11

A=3 and b= 4 what does b^a=

1 answer:

creativ13 [48]3 years ago

6 0

Answer:

b^a= 4^3 =64

Step-by-step explanation:

4^3

that is 4*4*4

hope this helped!

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15 + brainliest help me please

Fiesta28 [93]

2f +4f +2 -3
combine the like terms to get 6f-1

so yes they are equivalent

2f+4f+2-3 at f=3 would also be 17

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2 years ago

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Which graphs show continuous data?<br><br> Select each correct answer.

LenaWriter [7]

Answer:

its the first graph in the first one and the same thing with the second graph in the number 2 pleaes brailnliest

Step-by-step explanation:

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2 years ago

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A statistics instructor believes that fewer than 20% of Evergreen Valley College (EVC) students attended the opening night midni

Alex17521 [72]

Answer: It is believed that exactly 20% of Evergreen Valley college students attended the opening night midnight showing of the latest harry potter movie.

Step-by-step explanation:

Since we have given that

n = 84

x = 11

So, $\hat{p}=\dfrac{x}{n}=\dfrac{11}{84}=0.13$

p = 0.20

So, hypothesis:

$H_0:p=\hat{p}\\\\H_a:\hat{p}$

so, test statistic value would be

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.13-0.20}{\sqrt{\dfrac{0.2\times 0.8}{84}}}\\\\z=-1.604$

At 1% level of significance, critical value would be

z= 2.58

Since 2.58>-1.604

So, We will accept the null hypothesis.

Hence, It is believed that exactly 20% of Evergreen Valley college students attended the opening night midnight showing of the latest harry potter movie.

4 0

3 years ago

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Solve for y.<br> 6/11= y/3.

borishaifa [10]

The answer it is 18/11

8 0

3 years ago

In a study of the accuracy of fast food drive-through orders, one restaurant had 36 orders that were not accurate among 324 ord

tia_tia [17]

Answer:

We do not have sufficient evidence to reject the claim that ,the rate of inaccurate orders is equal to 10%.

Step-by-step explanation:

We want to use a 0.01 significance level to test the claim that the rate of inaccurate orders is equal to 10%.

We set up our hypothesis to get:

$H_0:p=0.10$ ------->null hypothesis

$H_1:p\ne0.10$ ------>alternate hypothesis

This means that: $p_0=0.10$

Also, we have that, one restaurant had 36 orders that were not accurate among 324 orders observed.

This implies that: $\hat p=\frac{36}{324}=0.11$

The test statistics is given by:

$z=\frac{\hat p-p_0}{\sqrt{\frac{p_0(1-p_0)}{n} } }$

We substitute to obtain:

$z=\frac{0.11-0.1}{\sqrt{\frac{0.1(1-0.1)}{324} } }$

This simplifies to:

$z=0.6$

We need to calculate our p-value.

P(z>0.6)=0.2743

Since this is a two tailed test, we multiply the probability by:

The p-value is 2(0.2723)=0.5486

Since the significance level is less than the p-value, we fail to reject the null hypothesis.

We do not have sufficient evidence to reject the claim that ,the rate of inaccurate orders is equal to 10%.

3 0

3 years ago