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devlian [24]
3 years ago
3

Which function is shown in the graph below? On a coordinate plane, a curve goes through (0.33, negative 1), (1, 0), and (3, 1).

y = log Subscript 0.4 Baseline x y = log Subscript 1 Baseline x y = log Subscript 3 Baseline x y = log Subscript 10 Baseline x

Mathematics
2 answers:
GrogVix [38]3 years ago
7 0

Answer:

<u>y = ㏒₃ x</u>

Step-by-step explanation:

Given: the points (0.33, -1), (1, 0), and (3, 1)

We will check which function goes through the previous points

we will use the point (3,1)

1) y = ㏒₀.₄ x

㏒₀.₄ x = ㏒₀.₄ 3 = -1.199 ≠ 1

2) y = ㏒₁ x

㏒₁ x = ㏒₁ 3 ⇒ unlogic  condition

3) y = ㏒₃ x

㏒₃ x = ㏒₃ 3 = 1

4) y = ㏒₁₀ x

㏒₁₀ x = ㏒₁₀ 3 = 0.477 ≠ 1

So, from the previous explanation:

The function is y = ㏒₃ x

Another solution;

by drawing the four function we will find which function goes through the points (0.33, -1), (1, 0), and (3, 1)

See the attached figure.

<u>So, the answer is y = ㏒₃ x</u>

Nadya [2.5K]3 years ago
7 0

Answer:

The answer is C on ed.

Step-by-step explanation:

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