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Ymorist [56]
3 years ago
15

An amount of money that is deposited or borrowed that earns or is charged interest is called a what?

Mathematics
1 answer:
lesya692 [45]3 years ago
5 0

Answer:

the principal

Step-by-step explanation:

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Express 0.96 as an percent
enyata [817]

Answer:

96%

Step-by-step explanation:

0.96 × 100/100

(0.96 × 100)× 1/100 = 96/100

percentage = 96%

6 0
3 years ago
Read 2 more answers
Can you please help me again.
Jobisdone [24]

Answer: h = 17

Step-by-step explanation: As a general rule, if an equation has any fractions in it, try to get rid of those fractions as soon as possible.

The quickest way to get rid of a fraction is to multiply both

sides of the equation by the denominator of the fraction.

So in this problem, we can get rid of the fraction in our

first step by multiplying both sides of the equation by 4.

On the left, the 4's cancel and on the right, 1(4) is 4.

Now we have h - 13 = 4.

Since 13 is being subtracted from <em>h</em>, to get <em>h</em> by itself,

we need to add 13 to both sides of the equation to get h = 17.

Now, we can check our answer by plugging 17 back

into the original equation shown below in italics.

\frac{(17) - 13}{4} = 1

\frac{(4)}{4} = 1  true statement

3 0
3 years ago
Hi please help :)
Debora [2.8K]
Hey mate 

It is C. 0 because there is no b in the <span>equation</span>
3 0
3 years ago
Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125
liq [111]

For the given equation;

(3x-5)^2=-125

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}

Now that we have expanded the left side of the equation, we would have;

\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}

ANSWER:

x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}

3 0
1 year ago
What is ∑n=15[5(−2)n−1] equal to?
kicyunya [14]

Answer:

Although the notation is sloppy, I will assume based on former questions of the same that "∑n=15[5(−2)^n−1]" translates mathematically to . Please correct me, though, if this in incorrect.

Anyway, there is neat formula that will deal with question very quickly. It is the following:

Sn is the sum of the geometric series

a1 is the first term in the series

r is the common ratio

n is the number of terms in the finite geometric series

Let's use this formula to our advantage! However, there are two variables that we do not know: a1 and n. Let's start with a1.The first term in the series is when n=1, so let's determine what that is.

6 0
3 years ago
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