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joja [24]
3 years ago
7

Bill can hit a bucket of 323 golf balls in 17 hours.

Mathematics
2 answers:
Vanyuwa [196]3 years ago
3 0
323/17 is 19 19*23 is 437 so 437 golf balls
ser-zykov [4K]3 years ago
3 0
437 golf balls for sure
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Paul purchased a used vehicle that depreciates under a straight-line method.
netineya [11]

Answer:

Option B. $900

Step-by-step explanation:

Let

y ----> the value of the car

x ----> the time in years

we know that

The linear function in slope intercept form is equal to

y=mx+b

where

m is the slope or the depreciation rate

b is the y-intercept or initial value of the car

we have

The y-intercept or initial value is equal to

b=\$5,000

y=mx+5,000

we have the ordered pair (5,500)

substitute the value of x and the value of y of the ordered pair in the linear equation and solve for m

500=m(5)+5,000

5m=500-5,000\\5m=-4,500\\m=-\$900\ per\ year

Is negative because is a decreasing function

The linear equation is equal to

y=-900x+5,000

therefore

It would depreciate $900 each year.

4 0
3 years ago
Find the unit rate for 1/2 mile in 3/10 hour
babunello [35]

Answer:

1 mile for every 0.6 hours

Step-by-step explanation:

0.5 x 2 = 1

3/10 x 2 = 6/10

2 miles = 1.2 hours

4 0
3 years ago
In a right triangle, a and b are the lengths of the legs and c is the length of the hypotenuse. If a=18 centimeters and b=80 cen
zzz [600]

Answer:

c=82 cm

Step-by-step explanation:

hope this helps

8 0
3 years ago
Read 2 more answers
3. What is the value of 42 – 2(3 • 5+ 1)?
sp2606 [1]

Answer:

10

Step-by-step explanation:

6 0
3 years ago
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The general manager, marketing director, and 3 other employees of Company A are hosting a visit by the vice president and 2 othe
yawa3891 [41]

Solution :

Let the three places be 1, 2, 3, 4, 5, 6, 7, 8

a). Number of the cases when a general manager is the next to a vice president is equal to 7 and the these 2 can be arranged in 21 ways. So the total number of ways = 7 x 2

                  = 14

[(1,2)(2,1) (2,3)(3,2) (3,4)(4,3) (4,5)(5,4) (5,6)(6,5) (6,7)(7,8) (8,7)(7,6)]

Therefore the required probability is

  $=\frac{14}{8!}$

 = $\frac{14}{40320} = 0.000347$

b). The probability that the marketing director to be placed in the leftmost position is

   $=\frac{7!}{8!}$

  $=\frac{1}{8} = 0.125$

c). The two events are not independent because

   $P(A \cap B) \neq P(A) \times P(B)$

  $\frac{12}{8!} \neq \frac{14}{8!} \times \frac{1}{8}$

where A is the case a and B is the case b.

8 0
3 years ago
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