Answer:
66600 ft
Step-by-step explanation:
First draw a rectangle and draw a diagonal line in the middle. The line makes two triangles, and the line itself is the hypotenuse. So, to find hypotenuse, the formula is:
a^2 + b^2 = c^2
The variable c defines the hypotenuse. Therefore:
a = 150
b = 210
Let's solve:
150^2 + 210^2 = c^2
22500 + 44100 = c^2
66600 = c^2
Therefore, in conclusion, the result we are getting is 66600 ft.
<u><em>Hope This Helps!</em></u>
<span>Compatible </span>numbers for 256...
1. Rounded to the nearest hundred = 200
2. Rounded to the nearest tens place = 260
Compatible numbers for 321...
1. Rounded to the nearest hundred = 300
2. Rounded to the nearest tens place = 320
I hope this helps! :)
Answer:
About 5043.58
Step-by-step explanation:
The standard form for an exponential decay after t time is:

Where a is the initial value, r is the rate decay, t is the time that has passed, and d is the amount of time it takes for 1 cycle.
The initial value is 9800. So a = 9800.
The quantity cuts in half. So, r = 1/2.
And it cuts in half every 6 days. For this question, we will convert this to hours. 6 days = 144 hours. So, we can let d = 144, where t will be in hours.
Therefore, our function is:

Where t is the amount of time that has passed, in hours.
Then the quantity left after 138 hours will be:

Answer:
d because its big
Step-by-step explanation:
The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>
From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3 ![\sqrt[8]{15}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B15%7D)
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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