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4 years ago

On square PQRS below, if Q is located at (7,0) and R is located at (5,-8) what is the length of SR

Mathematics

1 answer:

jenyasd209 [6]4 years ago

8 0

the length of SR is $2\sqrt{17}$ .

Step-by-step explanation:

Here we have , On square PQRS below, if Q is located at (7,0) and R is located at (5,-8) . We need to find Length of side SR . Let's find out:

We know that , In a square there are 4 sides , and length of every side is same . So side length of SR = side length of QR . Now , Let's find side length of QR .

We know that distance between two points $Q(x_1,y_1),R(x_2,y_2)$ given by :

⇒ $QR = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Two points given are $Q(7,0), R(5,-8)$ :

⇒ $QR = \sqrt{5-7)^2+(-8-0)^2}$

⇒ $QR = \sqrt{(2)^2+(-8)^2}$

⇒ $QR = \sqrt{4+64}$

⇒ $QR = \sqrt{68}$

⇒ $QR = 2\sqrt{17}$

But QR=SR , Therefore , the length of SR is $2\sqrt{17}$ .

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olga2289 [7]

Answer:

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Step-by-step explanation:

Tax paid = 7% of $23

= 0.07*23

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3 years ago

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The sum of the square of a positive number and the square of 2 more than the number is 130. what is the number

qaws [65]

Let x be a positive number

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Answer: the number is 7.

Check:
7² + (7+2)² = 49 + 9² = 49 + 81 = 130

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3 years ago

There are 6 people in George's family. How much did George's mom pay for tickets? Show how you found your solution.

victus00 [196]

Answer:

$75

Step-by-step explanation:

To find out how much George's mom paid for the 6 tickets, first find the unit rate, that is cost per ticket.

The unit rate/constant of proportionality between cost of tickets (y) and number of tickets (x) can be calculated using the coordinates of any points on the graph.

Using (4, 50), this means that 4 tickets cost $50.

Unit rate/constant of proportionality = y/x = 50/4 = 12.5

This means a ticket costs $12.5.

Therefore, 6 tickets would cost:

6 tickets × $12.5 = $75.

George's mom paid $75 for the tickets?

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3 years ago

Find the first six terms of the sequence.

shutvik [7]

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3 years ago

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Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

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Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,

$undefined$

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1 year ago