On square PQRS below, if Q is located at (7,0) and R is located at (5,-8) what is the length of SR

Mathematics

1 answer:

jenyasd209 [6]3 years ago

8 0

the length of SR is $2\sqrt{17}$ .

Step-by-step explanation:

Here we have , On square PQRS below, if Q is located at (7,0) and R is located at (5,-8) . We need to find Length of side SR . Let's find out:

We know that , In a square there are 4 sides , and length of every side is same . So side length of SR = side length of QR . Now , Let's find side length of QR .

We know that distance between two points $Q(x_1,y_1),R(x_2,y_2)$ given by :

⇒ $QR = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Two points given are $Q(7,0), R(5,-8)$ :

⇒ $QR = \sqrt{5-7)^2+(-8-0)^2}$

⇒ $QR = \sqrt{(2)^2+(-8)^2}$

⇒ $QR = \sqrt{4+64}$

⇒ $QR = \sqrt{68}$

⇒ $QR = 2\sqrt{17}$

But QR=SR , Therefore , the length of SR is $2\sqrt{17}$ .

You might be interested in

Examine the following three premises: i. All kids who have a smartphone play mobile legends.

atroni [7]

Answer:

The increasing number of students who are hooked on playing online mobile games (OMG) is alarming. As such, this study was realized to address the problem. This study assessed the gaming profile towards OMG and its relation to the academic performance of the engineering students of Eastern Visayas State University Tanauan Campus (EVSUTC). Specifically, the study investigated the correlation between student's number of hours spent on playing OMG (at school and home), commonly played OMG (at school and home), reasons for playing OMG and attitudes on playing OMG with academic performance utilizing Eta and Pearson r correlation analyses. A random sample of 134 student respondents were selected through purposive sampling of those who are playing OMG using their mobile phones. Descriptive correlational research design was utilized and a validated survey instrument was employed to gather the needed information. The findings revealed that majority of the students played mobile legends and spent mostly 2 hours playing OMG for a reason of boredom. The overall attitudes of the students on playing OMG were interpreted as Less Favorable (M=2.58, SD=1.13). Out of the independent variables being set in the study, the number of hours spent on playing OMG at home (r=-0.188, p=0.039) and commonly played OMG at school (r=0.203, p=0.045) were found significantly correlated with student's academic performance. Hence, the students' time spent on playing OMG at home and the type of games that students played at school have significant bearing to their academic performance. As such, delimiting student's usage of internet can be made to address the problem.

3 0

1 year ago

Using the porpotions: WHIP= (Walks+Hits) divide by Innings Pitched. The pitcher wants to lower his WHIP from 1.53 to 1.3. How ma

BaLLatris [955]

This relates to ur previous question....there were 85 innings last question and 130 walks + hits which gave a whip score of 1.53......so if he wants to lower his whip (without changing his walks or hits) to 1.3....
130 / (85 + x) = 1.3....multiply both sides by (85 + x)
130 = 1.3(85 + x)
130 = 110.50 + 1.3x
130 - 110.50 = 1.3x
19.5 = 1.3x
19.5 / 1.3 = x
15 = x

he would have to pitch 15 more innings without any walks or hits to reach a goal of 1.3 whip score. This is not a reasonable goal.....have u ever seen a baseball game where a pitcher pitched 15 innings without any walks or hits ? And since a game consists of 9 innings....he would be 3 innings short of 2 games (thats if they dont go into overtime), and he would have to pitch a no hitter....and that is highly unlikely.

7 0

3 years ago

Find the product. (−x−3)(2x2+5x+8)=

harina [27]

$( - x - 3)(2 {x}^{2} + 5x + 8) = \\ = - 2 {x}^{3} - 5 {x}^{2} - 8x - 6 {x}^{2} - 15x - 24 = \\ = - 2 {x}^{3} - 11 {x}^{2} - 23x - 24$