Question

On square PQRS below, if Q is located at (7,0) and R is located at (5,-8) what is the length of SR

Answer 1

the length of SR is $2\sqrt{17}$ .

Step-by-step explanation:

Here we have , On square PQRS below, if Q is located at (7,0) and R is located at (5,-8) . We need to find Length of side SR . Let's find out:

We know  that  , In a square there are  4 sides , and length of every side is same . So side length of SR = side length of QR . Now , Let's find side length of QR .

We know that distance between two points $Q(x_1,y_1),R(x_2,y_2)$ given by :

⇒ $QR = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Two points given are $Q(7,0), R(5,-8)$ :

⇒ $QR = \sqrt{5-7)^2+(-8-0)^2}$

⇒ $QR = \sqrt{(2)^2+(-8)^2}$

⇒ $QR = \sqrt{4+64}$

⇒ $QR = \sqrt{68}$

⇒ $QR = 2\sqrt{17}$

But QR=SR , Therefore , the length of SR is $2\sqrt{17}$ .