All categories

3 years ago

Account has been hac ked what do i do????

1 answer:

4 0

Reset the password to something secure not abc123 or something like that for sure and if it continues I would just delete it and make a new one good luck!

You might be interested in

Which expression is equivalent to (5g^4+5g^3-17g^2+6g)-(3g^4+6g^3-7g^2-12)/g+2

ankoles [38]

Option C:

$2 g^{3}-5 g^{2}+6$

Solution:

Given expression:

$$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}$

To find which expression is equal to the given expression.

$$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}$

Expand the term $-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right):-3 g^{4}-6 g^{3}+7 g^{2}+12$

$$=\frac{5 g^{4}+5 g^{3}-17 g^{2}+6 g- 3 g^{4}-6 g^{3}+7 g^{2}+12}{g+2}$

Arrange the like terms together.

$$=\frac{5 g^{4}- 3 g^{4}+5 g^{3}-6 g^{3}-17 g^{2}+7 g^{2}+6 g+12}{g+2}$

$$=\frac{2 g^{4}- g^{3}-10 g^{2}+6 g+12}{g+2}$

Factor the numerator $2 g^{4}-g^{3}-10 g^{2}+6 g+12=(g+2)\left(2 g^{3}-5 g^{2}+6\right)$

$$=\frac{(g+2)\left(2 g^{3}-5 g^{2}+6\right)}{g+2}$

Cancel the common factor g + 2, we get

$=2 g^{3}-5 g^{2}+6$

Hence option C is the correct answer.

8 0

2 years ago

Read 2 more answers

What is the range? 6 7 8 7 10

jeka94

Range= 4

Range is the highest number minus the lowest number, 10-6=4

4 0

2 years ago

Read 2 more answers

Express the ratio 2 to 3 and 8 to 9 in lowest terms

Alex73 [517]

$\dfrac{2}{3}:\dfrac{8}{9}=\left(9\cdot\dfrac{2}{3}\right):\left(9\cdot\dfrac{8}{9}\right)=(3\cdot2):(1\cdot8)\\\\=6:8=\dfrac{6}{2}:\dfrac{8}{2}=3:4\\\\Answer:\ \boxed{\dfrac{2}{3}:\dfrac{8}{9}=3:4}$

8 0

3 years ago

What is 4 1/5+3 1/10 a. 7 2/15 b. 7 3/10 c. 7 1/5 d. 7 1/50

Black_prince [1.1K]

7 1/5th is the anwser but thats easy your just being lazy i think

7 0

3 years ago

4x²-y²=171 and 2x-y=9, value of 2x+y

11111nata11111 [884]

So you will need to solve for x and y before evaluating 2x+y....

2x-y=9, y=2x-9 now this will make 4x^2-y^2=171 become:

4x^2-(2x-9)^2=171

4x^2-(4x^2-36x+81)=171

36x-81=171

36x=252

x=7, now we can use 2x-y=9 to solve for y...

2(7)-y=9

14-y=9

-y=-5

y=5

now we know that x=7 and y=5, 2x+y becomes:

2(7)+5

14+5

19

8 0

3 years ago