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Elan Coil [88]
3 years ago
6

Which statements are true about the standard normal distribution? The standard normal distribution is______.

Mathematics
1 answer:
almond37 [142]3 years ago
6 0

Answer:

A) defined by the two parameters μ = 0, σ =1

(B) symmetric

(D) a density curve.

(E) unimodal

(F) referred to as a bell-curve

Step-by-step explanation:

We have to state the properties of a standard normal distribution.

A) defined by the two parameters μ = 0, σ =1

The standard normal distribution has a mean 0 and standard deviation of 1.

(B) symmetric

The normal distribution is symmetric around the mean that is area under the curve on the left side of mean is same as the area on the right side of mean.

(C) defined by the two parameters μ = 1, σ = 0

The given statement is false in regard with standard normal distribution.

(D) a density curve.

A density curve is a curve that represents the probability for a distribution and area under the curve is 1. The standard normal distribution is a density curve.

(E) unimodal

The standard normal distribution is unimodal that is it have only one value that occurs most frequently and for standard normal distribution the modal value is 0.

(F) referred to as a bell-curve

The standard normal distribution curve has a shape similar to a bell and referred to as bell-curve.

(G) skewed

The standard normal distribution is not skewed. It is symmetric.

(H) multimodal

The standard normal distribution has a unique mode.

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andriy [413]
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Since parabola passes through the point (2,−15) then 
−15 = 4a + 2b + c

Since parabola passes through the point (-5,-29), then
−29 = 25a − 5b + c

Since parabola passes through the point (−3,−5), then 
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Thus, we obtained following system:
4a + 2b + c = −15
25a − 5b + c = −29
9a − 3b + c = −5

Solving it we get that 
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Thus, equation of parabola is
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____________________

Rewriting in the form of 
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i) -2x² - 4x + 1 = y

ii) -3x² - 7x = y - 11
(-3x² and -7x are isolated)

iii) -3x² - 7x - 49/36 = y - 1 - 49/36
(Adding -49/36 to both sides to get perfect square on LHS)

iv) -3(x² + 7/3x + 49/36) = y - 3
(Taking out -3 common from LHS)

v) -3(x + 7/6)² = y - 445/36 

vi) (x + 7/6)² = -⅓(y - 445/36) 
(Shifting -⅓ to RHS)

vii) (x + 1)² = 4(-1/12)(y - 445/36)
(Rewriting in the form of 4(-1/12) ; This is 4p) 


So, after rewriting the equation would be - 

(x + 7/6)² = 4(-⅛)(y - 445/36)

__________________

I hope this is what you wanted.

Regards,
Divyanka♪
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Step-by-step explanation:

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