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3 years ago

True or false; If two planes cross one another, then their intersection is two lines.

2 answers:

8 0

Hey There!

The answer would be true, because if your planes are not parallel, they're eventually going to meet and intersect.

Hope this helps!

Vlad1618 [11]3 years ago

5 0

If they intersect eachother then the answer is true

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Write a polynomial of degree 3 whose only roots are x=2 and x=2/5. Is there another polynomial of degree 3 that has the same roo

TEA [102]

One such polynomial might be

$(x-2)\left(x-\dfrac25\right)^2$

Another with the same roots would be

$(x-2)^2\left(x-\dfrac25\right)$

7 0

2 years ago

Read 2 more answers

Help me plz :3 :) :x :P

Sonbull [250]

Yes, she is correct
1/2 + 1/2 = 1 or 0.5 + 0.5 = 1 so half of a wall plus half of a wall equals one hole wall.

That's as simple as I can put it mathematical reasoning. I hope this helps

7 0

3 years ago

Convert 6 1/2 ft into in

iogann1982 [59]

78 inches if you you know that a foot is 12 inches you can add 12 for every inch then add 6 for the half making it 78 inches.

6 0

2 years ago

Two investments totallng $47,500 produce an annual income of $3000. One investment ylelds 9% per year, while the other yields 6%

enot [183]

Answer:

The correct answer is "$5000".

Step-by-step explanation:

The given values are:

Two investments totaling,

= $47,500

Annual income,

= $3000

One investment yields per year,

= 9%

Other yield,

= 6%

Let,

The amount invested in 9% will be "x".
The amount invested in 6% will be " $47,500-x$ ".

Now,

⇒ $0.09x+0.06(47,500-x)=3000$

⇒ $0.09x+2850-0.06x=3000$

⇒ $0.03x+2850=3000$

⇒ $0.03x=150$

⇒ $x=\frac{150}{0.03}$

⇒ $x=5000$

5 0

2 years ago

You are graphing Square ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the square: A(4,

Kitty [74]

Answer:

D(4,-3)

Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

Let the coordinate of the fourth vertex be D(x,y).

We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.

The diagonals are BD and AC

Midpoint of BD = Midpoint of AC

$\left(\dfrac{8+x}{2},\dfrac{-7+y}{2}\right) =\left(\dfrac{4+8}{2},\dfrac{-7+(-3)}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(\dfrac{12}{2},\dfrac{-10}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(6,-5\right)\\$Therefore$:\\\dfrac{8+x}{2}=6\\8+x=12\\x=12-8\\x=4\\$Similarly$\\\dfrac{y-7}{2}=-5\\y-7=-5*2\\y-7=-10\\y=-10+7=-3$

The coordinates of the fourth vertex is D(4,-3)

3 0

3 years ago