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Answer:</u></h2>
Which ordered pairs are in the solution set of the system of linear inequalities?
y > Negative one-halfx
y < One-halfx + 1
On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 0) and (4, negative 2). Everything above the line is shaded. The second dashed line has a positive slope and goes through (negative 2, 0) and (2, 2). Everything below the line is shaded.
(5, –2), (3, 1), (–4, 2)
(5, –2), (3, –1), (4, –3)
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(5, –2), (3, 1), (4, 2)</u></h2>
(5, –2), (–3, 1), (4, 2)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
Conjugate radicals.
Step-by-step explanation:
The two roots a+sqrb and a-sqr b are called conjugate radicals.
Answer:
116 Sq inches
Step-by-step explanation:
3×area of rectangle (l× b) + 2 area of triangle (1/2 b h)
3×32 + 2×1/2×4×5
96 + 20
116
The proof is given below. Please go through it.
Step-by-step explanation:
To solve Δ ABC ≅ Δ DBC
From Δ ABC and Δ DBC
AB = BD (given)
AC = CD (given)
BC is common side
By SSS condition Δ ABC ≅ Δ DBC ( proved)
To solve Δ EHF ≅ Δ GHF
Δ EHF and Δ GHF
EH = HG ( given)
∠ EFH = ∠ GFH ( each angle is 90°)
HF is common side
By RHS condition
Δ EHF ≅ Δ GHF