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noname [10]
3 years ago
6

On a given morning the temperature was 71°F. The temperature dropped 5°F and then rose 8°F. How much does the temperature need t

o rise or fall to return to the initial temperature of 71°F?
Mathematics
2 answers:
professor190 [17]3 years ago
7 0

Answer:

Step-by-step explanation:

Temperature needs to fall by 3 degrees

morpeh [17]3 years ago
4 0

Answer:

  fall 3°

Step-by-step explanation:

To return to the same value, the sum of rises must be the same as the sum of falls. The temperature must fall 3 °F for the total of falls to be 8 °F, the same as the rise.

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A car manufacturer announced that next year the price of a certain model car would increase by 3.5%. This year the price is $15,
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3 years ago
Solve for x.<br><br> A. 37<br> B. 27<br> C. 30<br> D. 31
dexar [7]

Answer:

B

Step-by-step explanation:

The formula for finding the relationship between a secant and a tangent is

tangent length ^2 = external segment secant/full length of secant

In this case

60^2 = 48*(x + 48)                   Expand

3600 = 48*(x + 48)                  Remove the brackets/

3600 = 48x + 48^2                 Expand

3600 = 48x + 2304                Subtract 2304 from both sides

3600 - 2304 = 48x              

1296 = 48x                              Divide both sides by 48

1296 / 48 = x        

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8 0
3 years ago
The width of a rectangle is three more than twice the length. The perimeter is 96 inches. Find the length and the width.
ExtremeBDS [4]

Answer:

The length of the rectangle is 15 inches and the width is 33 inches

Step-by-step explanation:

The dimensions for the rectangle are as follows:

L=L and W=2L+3

The equation for perimeter of a rectangle is:

P=2l+2w

To Solve:

1. Plug values into perimeter equation

96=2(L)+2(2L+3)

2. Simplify the equation above.

96=2L+4L+6

3. Combine like terms:

96=6L+6

4. Solve for L by subtracting 6 from both sides:

90=6L

5. Solve for L by dividing both sides by 6:

15=L.

6. Plug 15 into the equation for the width:

2(15)+3=w

30+3=w.

7 0
3 years ago
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