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Serga [27]
3 years ago
7

No files just type it in please and thank you<3

Mathematics
1 answer:
damaskus [11]3 years ago
6 0

Answer:

Option C is correct

Step-by-step explanation:

8 + 8 + 8 + 8 + 8 + 8 = 48

6 \times 8 = 48

<h3>Hope it is helpful...</h3>
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2) 83,97,85,84,96, 80,80,87,91<br> Mean median and mode
marusya05 [52]

\text {Hi! Let's Solve this Problem!}

\text {Before you find the Mean, Medina and Mode you must put the numbers in order.}

\text {Before: 83, 97, 85, 84, 96, 80, 80, 87, 91}\\\text {After: 80, 80, 83, 84, 85, 87, 91, 96, 97}

\underline {\text {Mean}}

\text {To Find the Mean you must Add all the Numbers then Divide.}

\text {Add:} \text 80+80+83+84+85+87+91+96+97=\fbox {783}}

\text {Divide:} \text {783/9=}

\text {The Mean Is:}

\fbox {87}

\underline {\text Median}}

\text {To find the Median you find the number that's in the middle of the set.}

\text {Put your Left Pointer Finger on 83. Put your Right Pointer Finger on 91.}

\text {Move your Left Finger to the Right. Move your Right Finger to the Left.}

\text {Once your Left Finger makes it to 84 and your Right Finger makes it to 87} \text {it shows that 85 is left in the middle.}

\text {The Median Is:}

\fbox {85}

\underline {\text {Mode}}

\text {Finding the Mode means finding the number} \text { that shows the most in the number set given.}

\text {Since 80 is the number that is showing more than any other number} \text {this tells us that 80 is our Mode.}

\text {The Mode Is:}

\fbox {80}

\text {Best of Luck!}

4 0
4 years ago
At a museum, the admission price for children is $9 and the admission price for adults is $18. The total amount the museum colle
anygoal [31]

Answer:

x + y = 330  and 9x + 16y = 4650

Step-by-step explanation:

At a museum, the admission price for children is $9 and the admission price for adults is $18. The total amount the museum collects in admissions for the day is $4959. The total number of visitors is 319.

x = number of children

y = number of adults

x + y = 330

9x + 16y = 4650

4 0
4 years ago
Help me, Thanks!!
Marrrta [24]

2.) dT/dt = -t^2 + 3t

dT = (-t^2 + 3t)dt

T = -t^3/3 + 3t^2/2 + C

at 4:00 AM

80 = -4^3/3 + 3*4^2/2 + C

C = 80 + 4^3/3 - 3*4^2/2

C = 77.33

T = -t^3/3 + 3t^2/2 + 77.33

at 8:00 AM

T = -8^3/3 + 3*8^2/2 + 77.33

T = 2.67 deg

5 0
3 years ago
If <br>4x+(y+x)=180<br>what is x? what is y?​
uysha [10]

Step-by-step explanation:

4x+(y+x)=180\\\\\text{Solve for}\ x:\\\\4x+y+x=180\qquad\text{combine like terms}\\\\(4x+x)+y=180\qquad\text{subtract}\ y\ \text{from both sides}\\\\5x=180-y\qquad\text{divide both sides by 5}\\\\\dfrac{5x}{5}=\dfrac{180-y}{5}\\\\\boxed{x=\dfrac{180-y}{5}}\\\\\text{Solve for}\ y:\\\\5x+y=180\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\\boxed{y=180-5x}

7 0
3 years ago
suppose you have 76 feet of fencing to enclose a rectangular dog pen. The function A=38x-x^2, where x= width, gives you the area
yan [13]
If A=38x-x^2 then

dA/dx=38-2x

d2A/dx2=-2

Since the acceleration, d2A/dx2 is a constant negative, when velocity, dA/dx=0, it will be an absolute maximum for A(x)

dA/dx=0 only when 38=2x, x=19

A(19)=38(19)-19^2

A(19)=722-361

A(19)=361 ft^2

So the maximum possible area is 361 ft^2

(This will always be true as the maximum possible area enclosed by a given amount of material will always be a perfect square...)
3 0
3 years ago
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