Question Continuation
A customer who owns shares in just one fund is to be selected at random.
a. What is the probability that the selected individual owns shares in the balanced fund?
b. What is the probability that the individual owns shares in a bond fund
Answer:
a. 0.08
b. 0.28
Step-by-step explanation:
Given
Money-market 22%
High-risk stock 17%
Short bond 11%
Moderate-risk stock 25%
Intermediate bond 12%
Balanced 8%
Long bond 5%
a. What is the probability that the selected individual owns shares in the balanced fund?
Let P(Balanced) = The probability that the selected individual owns shares in the balanced fund
P(Balanced) is given as 8% from the above table
So, P(Balanced) = 8/100
P(Balanced) = 0.08
b. What is the probability that the individual owns shares in a bond fund
Let P(Bond) = The probability that the individual owns shares in a bund fund
P(Bond) = P(Short Bond) + P(Intermediate Bond) + P(Long Bond)
P(Short Bond) = 11%
P(Intermediate Bond) = 12%
P(Long Bond) = 5%
So, P(Bond) = 11% + 12% + 5%
P(Bond) = 28%
P(Bond) = 0.28
The length of the hypotenuse of a right triangle can be found using the Pythagorean theorem, which states that the square of the length of the hypotenuse equals the sum of the squares of the lengths of the other two sides.
Answer:
y = -6, x =2
Step-by-step explanation:
To solve by elimination, you have to line both equations up together. Then, you multiply both equations until one variable is removed.
2x+y = -2
5x + 3y = - 8
There are many different ways to solve an elimination problem, but generally you should look for the simplest route. Here, I would multiply the top equation by -3.
-6x -3y = 6
5x +3y = -8
Imagine you are adding the two equations together. You end up with
-x = -2
Then solve for x. In this situation, it is fairly simple. Take out a factor of -1.
x = 2
Finally, choose one of your beginning equations and plug your new-found x value back into the equation.
2(2) +y = -2
4 + y = -2
y = -6
Answer:
(9, 0)
Step-by-step explanation:
Maximum or minimum value occurs at the Corner. The points given are (0, 8), (5, 4) and (9, 0).
Substitute (0, 8) in the objective function.
We get P = 3(0) + 2(8) = 16
Now for (x , y) = (5, 4)
P = 3(5) + 2(4) = 15 + 8 = 23
At (9, 0) we get P = 3(9) + 2(0) = 27.
Clearly, we have the maximum value at (9, 0).
And the maximum value is 27.
