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Natalija [7]
3 years ago
5

I need help number 15​

Mathematics
1 answer:
AysviL [449]3 years ago
4 0

Answer:

(2, -4)

Search in the 4th Quadrant. (Bottom Right)

Move right 2 times.

Move down 4 times.

(-4, 2)

Search in the 2nd Quadrant. (Top Left)

Move left 4 times.

Move up 2 times.

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The half-life of lead is 22 years. How long will it take for a sample of this substance t decay to 80% of its original amount?
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Answer: 7 years

Step-by-step explanation:

t_{\frac{1}{2} } = In2 / ∧

since the half life is given , we have :

22 = In 2/ ∧

∧ = In2/22

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Recall the formula for half life:

\frac{N(t)}{N(0)} = e^{-∧t}

Therefore:

0.80 = e^{-0.032t}

Take the In of both sides

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t = In 0.80 / - 0.032

t = 7 years

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What is the product? startfraction 4 k 2 over k squared minus 4 endfraction times startfraction k minus 2 over 2 k 1 endfraction
Tcecarenko [31]

The product of the expression (\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1}  is the expression \frac{2}{k+2}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the expression:

(\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1} \\\\This\ can\ be\ simplified\ to:\\\\(\frac{2(2k+1)(k-2)}{(k+2)(k-2)(2k+1)}) \\\\=\frac{2}{k+2}

The product of the expression (\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1} is the expression \frac{2}{k+2}

Find out more on equation at: brainly.com/question/2972832

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