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Amiraneli [1.4K]
3 years ago
10

PLEASE HELP!!!

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
7 0
1)
7/6d+4/3=-1/3
7/6d=-5/3
d=-5/3×6/7
d=-10/7
2)
5 1/2-u=9/4
11/2-u=9/4
22/4-u=9/4
13/4=u
3 1/4=u
3)
-m-7/8=-10
-m-7/8=-80/8
-m=-73/8
m=73/8 or 9 1/8
4)
2/7=4/5+9q
10/35=28/35+9q
-18/35=9q
q=-18/35×1/9
q=-2/35. Hope it help!
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Bingel [31]

Answer:

m=25/12

Step-by-step explanation:

multiply the reciprocal of 2/5 on both sides

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A company has 10 trucks. A truck has 15 pallets. A pallet has 7 boxes. A box has 50 containers. A container has 3 plastic bags.
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Step-by-step explanation:

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Need help on these !! 13 and 14! Please!!
katen-ka-za [31]

Question # 13

Answer:

The required equation for the given function is <em>y = 4sin(x/2+2π/3) -2 , as shown attached graph diagram.</em>

<em>Step-by-step explanation: </em>

As the general sine function is given by

y=asin(bx+c)+d.......[A]

  • amplitude = a
  • period = 2π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • amplitude = a = 4
  • period = 4π
  • phase shift = -4π/3
  • Vertical shift = d = -2

As  

period = 2π ÷ b  

b = 2π/period

b = 2π/4π ∵ period = 4π

b = 1/2  

Also

Phase shift = -c/b

-4π/3 = -c/b ∵ phase shift = -4π/3

4π/3 = c/b  

c = b × 4π/3  

c = 1/2 × 4π/3  

c = 4π/6  

c = 2π/3

So, putting Amplitude ⇒ a = 4, Vertical shift ⇒ d = -2, b = 1/2 ,  

and c = 2π/3 in Equation [A] would bring us the required equation for the given function.

y=asin(bx+c)+d

y = 4sin(x/2+2π/3)+(-2)

y = 4sin(x/2+2π/3) -2            

<em>Note: The graph is also shown in attached diagram.</em>

                                             Question # 14

<em>Answer:</em>

The required equation for the given function is y = cot(x+π/3)+2, as shown in attached graph diagram.

<em>Step-by-step explanation: </em>

As the general cotangent function is given by

y=acot(bx+c)+d.......[A]

  • amplitude = a
  • period = π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • period = π
  • phase shift = -π/3
  • Vertical shift = d = 2

As  

period = π ÷ b  

b = π/period

b = π/π ∵ period = 4π

b = 1  

Also

Phase shift = -c/b

-π/3 = -c/b ∵ phase shift = -π/3

π/3 = c/b  

c = b × π/3  

c = 1 × π/3  

c = π/3

So, putting vertical shift ⇒ d = 2, b = 1 and   c = π/3 in Equation [A] would bring us the required equation for the given function.

y=acot(bx+c)+d

y = cot(x+π/3)+2

<em>Note: The graph is also shown in attached diagram.</em>

Keywords: amplitude, period , phase shift , vertical shift

Learn more about trigonometric functions of equations from brainly.com/question/2643311

#learnwithBrainly

7 0
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larisa86 [58]

Answer:

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Step-by-step explanation:

i just figured it out i really don't have one but i hope it helps

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Tpy6a [65]

Answer:

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Step-by-step explanation:

V=s^3

V=2.3x2.3x2.3

V=12.167

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