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Aliun [14]
3 years ago
6

Evaluate 4(2a - b) when a = -1 and b = 5 A -48 B -28 C -12 D 32

Mathematics
1 answer:
emmainna [20.7K]3 years ago
7 0
I'd suggest you enclose -1 and 5 within brackets as shown:


4( 2[-1] - [5] ).  Do the work within parentheses FIRST:  4( -7 ).
Then multiply as indicated:  -28
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5/6 is bigger than 9/17
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expeople1 [14]
3/3 or it could be 1
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Challenge A warehouse store sells 5.5-ounce cans of tuna in packages of 8. A package of 8 cans
Stolb23 [73]

Answer:

Step-by-step explanation:

the warehouse is the best buy because you get 44oz off tuna but if you buy the three pack you get 19.5oz and if you buy the five pack from store you 22.5oz of tuna

so the warehouse has the best deal on tuna

4 0
3 years ago
Simplify the rational expression. State any restrictions on the variable.
ExtremeBDS [4]

we are given

\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}

Firstly, we will factor numerators and denominators

\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}=\frac{(n^2-6)(n^2-4)}{(n^2-3)(n^2-6)}

we can see that

n^2 -6 is factor on both numerator and denominator

so, it will get cancelled

and n^2 -6 can not be equal to 0

so, one of restriction is

n^2-6\neq 0

n\neq -+ \sqrt{6}

we can simplify it

\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}=\frac{(n^2-4)}{(n^2-3)}

we know that denominator can not be zero

n^2-3\neq 0

n\neq -+ \sqrt{3}

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3 0
3 years ago
A true-false question is to be posed to a husband and wife team. Both the husband and the wife will give the correct answer with
marysya [2.9K]

Answer:

Choose either strategy both are equally successful

Step-by-step explanation:

Given:-

- The probability of success for both husband (H) and wife (W) are:

                              P ( W ) = 0.8 , P ( H ) = 0.8

Find:-

- Which of the following is a better strategy for the couple?

Solution:-

Strategy 1

- First note that P ( W ) & P ( H ) are independent from one another, i.e the probability of giving correct answer of husband does not influences that of wife's.

- This strategy poses an event such that either wife knows the answer and answer it correctly or the husband knows and answers in correctly.

- We will assume that probability of either the husband or wife knowing the answer is 0.5 and the two events of knowing and answering correctly are independent. So,

                           P ( Wk ) = P (Hk) = 0.5

- The event P(S1) is:

                           P(S1) = P ( Hk & H ) + P ( Wk & W )

                           P(S1) = 0.5*0.8 + 0.5*0.8

                           P(S1) = 0.8

- Hence, the probability of success for strategy 1 is = 0.8

Strategy 2

- Both agree , then the common answer is selected otherwise, one of their answers is chosen at random.

- The success of strategy 2, will occur when both agree and are correct, wife is correct and answers while husband is not or husband is correct and he answers.

- The event P(S2) is:

                   P(S2) = P ( H & W ) + P ( H / W' & Hk ) + P ( H' / W & Wk )

                   P(S2) = P ( H & W ) + P ( H / W') P ( Hk ) + P ( H' / W) P (Wk)

                   P(S2) = P ( H & W ) + P ( H / W')*0.5  + P ( H' / W)*0.5

                   P(S2) = 0.5* [ P ( H & W ) + P ( H / W') ]  + 0.5* [ P ( H' / W) + P ( H & W )]

                   P(S2) = 0.5*P(H) + 0.5*P(W)

                   P(S2) = 0.5*0.8 + 0.5*0.8

                   P(S2) = 0.8

- Hence, the probability of success for strategy 2 is = 0.8

Both strategy give us the same probability of success.

                 

                       

4 0
3 years ago
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