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grin007 [14]
3 years ago
14

Write the phrase as an algerbraic expression. 4 times the sum of a number and 20

Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0
4 x (n + 20), pretty simple. :)
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The area of a rectangle is x^2-4/2x in.^2 and its length is (x+2)^2/2 in. What is the width in inches?
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Is b I’m sure check
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What is the equivalent factored form of 12x^4-42x^3-90x^2
Tanzania [10]
Factor the following:
12 x^4 - 42 x^3 - 90 x^2

Factor 6 x^2 out of 12 x^4 - 42 x^3 - 90 x^2:
6 x^2 (2 x^2 - 7 x - 15)

Factor the quadratic 2 x^2 - 7 x - 15. The coefficient of x^2 is 2 and the constant term is -15. The product of 2 and -15 is -30. The factors of -30 which sum to -7 are 3 and -10. So 2 x^2 - 7 x - 15 = 2 x^2 - 10 x + 3 x - 15 = x (2 x + 3) - 5 (2 x + 3):
6 x^2 x (2 x + 3) - 5 (2 x + 3)

Factor 2 x + 3 from x (2 x + 3) - 5 (2 x + 3):
Answer:  6 x^2 (2 x + 3) (x - 5)
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Pentagon ABCDE Is the image of pentagon ABCDE under a dilation with a scale factor of 3/2 What is the length of segment overline
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Answer:

4

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Differentiate y=x⁴(1-2x⁵)⁶(5-8x³)².​
Liula [17]

Step-by-step explanation:

Let y(x)=f(x)g(x)h(x) where

f(x) = x^4

g(x)= (1 -2x^5)^6

h(x)= (5 - 8x^3)^2

so that

y(x) = x^4(1 -2x^5)^6(5 - 8x^3)^2

Recall that the derivative of the product of functions is

y'(x)=f'(x)g(x)h(x)+f(x)g'(x)h(x)+f(x)g(x)h'(x)

so taking the derivatives of the individual functions, we get

f'(x) = 4x^3

g'(x) = 6(1 - 2x^5)^5(-10x^4)

h'(x) = 2(5 - 8x^3)(-24x^2)

So the derivative of y(x) is given by

y'(x) = 4x^3(1 -2x^5)^6(5 - 8x^3)^2 +  x^4 6(1 -2x^5)^5(-10x^4)(5 - 8x^3)^2 +  x^4(1 -2x^5)^6 2(5 - 8x^3)(-24x^2)

or

y'(x) = 4x^3(1 -2x^5)^6(5 - 8x^3)^2

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:- 60x^8(1 -2x^5)^5(5 - 8x^3)^2

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:- 48x^6(1 -2x^5)^6 2(5 - 8x^3)

3 0
3 years ago
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