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Burka [1]
3 years ago
13

X/2 + 4 < 18

Mathematics
2 answers:
Pani-rosa [81]3 years ago
6 0

Answer:

x<28

Step-by-step explanation:

Isolate x

First, subtract 4 on both sides

x/2+<14

Then, multiply both sides by 2 to get x alone

x<28

On a number line, there would be an open circle (not filled in dot) on 28, and the entire left side of the number line would be filled in

Firlakuza [10]3 years ago
6 0

Answer:

x<28

Step-by-step explanation:

x/2+4<18

multiply the 2 on both sides to get rid of it

x+8<36

isolate the x

x<28

on the number line, it's an open circle with the arrow pointing to the left.

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Hey honeys, anyone wanna help me out here? &lt;3
Sindrei [870]

Answer:

D:4

Step-by-step explanation:

12(4)-5=5(4)+23

43=43

Hope this helps

3 0
3 years ago
Without graphing, write the equation of the axis of symmetry for<br> f(x) = 4|x + 8] - 5.
iren [92.7K]

Answer:

The line of symmetry is x=8

Step-by-step explanation:

7 0
3 years ago
Can anyone answer this pls!!!!!!!!!!
gizmo_the_mogwai [7]

u₁₂ represents the amount of loan remaining after 12 years

<h3>How to interpret u₁₂?</h3>

The function is given as:

u₀ = 8000

u_n = u_{n-1}(1 + 0.054) - 500

Given that the subscript n in u_n represents number of years and u_n represents the amount left to be paid after n years.

We can conclude that:

u₁₂ represents the amount of loan remaining after 12 years

Read more about loan at
brainly.com/question/26011426

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6 0
2 years ago
24. To what fraction is the arrow pointing to
sp2606 [1]
Image? where is it? id love to help
3 0
4 years ago
5. Find the value(s) of x so that the line containing the points (2x + 3, x + 2) and (0, 2) is
Dvinal [7]

Answer:

  x = -2 or -9

Step-by-step explanation:

You want the values of x such that the line defined by the two points (2x+3, x+2) and (0, 2) is perpendicular to the line defined by the two points (x+2, -3-3x) and (8, -1).

<h3>Slope</h3>

The slope of a line is given by the slope formula:

  m = (y2 -y1)/(x2 -x1)

Using the formula, the slopes of the two lines are ...

  m1 = (2 -(x+2))/(0 -(2x+3)) = (-x)/(-2x-3) = x/(2x +3)

and

  m2 = (-1 -(-3-3x))/(8 -(x+2)) = (2+3x)/(6 -x)

<h3>Perpendicular lines</h3>

The slopes of perpendicular lines have product of -1:

  \dfrac{x}{2x+3}\cdot\dfrac{2+3x}{6-x}=-1\\\\x(3x+2)=(2x+3)(x-6)\qquad\text{multiply by $(2x+3)(6-x)$}\\\\3x^2+2x=2x^2-9x-18\qquad\text{eliminate parentheses}\\\\x^2+11x+18=0\qquad\text{put in standard form}\\\\(x+2)(x+9)=0\qquad\text{factor}

<h3>Solutions</h3>

The values of x that satisfy this equation are x = -2 and x = -9. The attached graphs show the lines for each of these cases.

4 0
1 year ago
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