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4 years ago

Which is the graph of f(x) = 100(0.7)x?

Mathematics

2 answers:

julia-pushkina [17]4 years ago

6 0

I'm assuming the function is f(x) = 100(0.7)^x. This is the same as y = 100(0.7)^x because y = f(x).

Plug in x = 0 to get
y = 100(0.7)^x
y = 100(0.7)^0
y = 100(1)
y = 100
So (x,y) = (0,100) is one point on this function curve

Plug in x = 2 to get
y = 100(0.7)^x
y = 100(0.7)^2
y = 100(0.49)
y = 49
So (x,y) = (2,49) is another point on this curve

In summary, the two points on this function curve are (0,100) and (2,49)

Rashid [163]4 years ago

3 0

Answer:

it is A

Step-by-step explanation:

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brilliants [131]

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3 years ago

Just look at the directions brainliest and thanks!

Crank

Answer:

b) Yes. Because it grows linearly, and have the proportions of 3. For each x you have an y 3 times bigger

Step-by-step explanation:

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The second part of the problem is where i need help. The answers i have there have been given by other tutors

tino4ka555 [31]

SOLUTION

From the given value

Since

$\sin u=\frac{7}{25}$

Then using trigonometrical ratios it follows

$\cos u=\frac{24}{25}$

Using hal -ngle it folows

$\begin{gathered} sin(\frac{u}{2})=\sqrt{\frac{1-\frac{24}{25}}{2}} \\ s\imaginaryI n(\frac{u}{2})=\sqrt{\frac{1}{50}} \end{gathered}$

Also

$\begin{gathered} cos(\frac{u}{2})=\pm\sqrt{\frac{1+\frac{24}{25}}{2}} \\ cos(\frac{u}{2})=\sqrt{\frac{49}{50}} \\ cos(\frac{u}{2})=7\sqrt{\frac{1}{50}} \end{gathered}$

Finally?

$\begin{gathered} \tan(\frac{u}{2})=\pm\sqrt{\frac{1-\frac{24}{25}}{1+\frac{24}{25}}} \\ \tan(\frac{u}{2})=\sqrt{\frac{1}{49}} \\ \tan(\frac{u}{2})=\frac{1}{7} \end{gathered}$

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Answer:

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Step-by-step explanation:

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Answer:

c = 5

Step-by-step explanation:

The Pythagorean theorem states that in every right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the respective lengths of the legs. It is the best-known proposition among those that have their own name in mathematics.

Pythagoras theorem

In every right triangle the square of the hypotenuse is equal to the sum of the squares of the legs.

If in a right triangle there are legs of length a and b the measure of the hypotenuse is c then the following relation is fulfilled:

$a^{2} +b^{2} =c^{2}$

With a = 3 and b = 4

$c=\sqrt{3^{2} +4^{2}} =\sqrt{9+16} =\sqrt{25} \\c=5$

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