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Kitty [74]
3 years ago
12

What does 5 = ? Having trouble on this homework don't understand the fraction's yet. Need help!

Mathematics
1 answer:
Katena32 [7]3 years ago
5 0
Okay, 5 can be equal 5/1, 10/2, 15/3, 20/4, etc. In other words, it means that some number over or divided the different number like some examples that shown above must equal 5. Hope it help!
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Answer it pls and explain too​
snow_tiger [21]

Answer:

  y-intercept: (0, 5); slope: 1/4

Step-by-step explanation:

The slope (m) is found from ...

  m = (y2 -y1)/(x2 -x1)

Using the first two points in the table, this is ...

  m = (8 -6)/(12 -4) = 2/8 = 1/4 . . . . . eliminates choices A and C

__

Then, the point-slope form of the equation of the line can be written as ...

  y -y1 = m(x -x1)

  y -6 = (1/4)(x -4) . . . fill in known values

  y = 1/4x -1 +6 . . . . . add 6

  y = 1/4x +5

Then the value of y when x=0 is ...

  y = 0 +5 = 5

So, the y-intercept is (0, 5) and the slope is 1/4, matching the last choice.

7 0
4 years ago
Find all values of x that make the equation true.<br> 3/x-4 = x-5/x
Svetllana [295]

Answer:

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Answers? Thanks so much in advance for any help :)
LuckyWell [14K]
13. AC=6 

sorry it's just a guess i'm like 99% sure tho
8 0
3 years ago
The data obtained from a random sample of track athletes showed that as the foot size of the athlete decreased, the average runn
Rufina [12.5K]

Answer:

The correct option is;

(3) The sample of track athletes show that there is a correlation between foot size and running speed

Step-by-step explanation:

The statements are analysed as follows;

(1) Smaller foot sizes cause track athletes to run slower.

The above statement is a conclusion and it infers more information than is contained in the question statement because there are other factors such as taller athletes run faster than average sized athletes

(2) The sample of track athletes shows a causal relationship between

foot size and running speed.

The above statement is similar to the one above as it is a milder conclusion and it infers more information than is contained in the question statement

(3) The sample of track athletes shows a correlation between foot size

and running speed.

The  above statement is correct as is directly supported by the data as it is a statement made based directly the data

(4) There is no correlation between foot size and running speed in

track athletes.

The above statement is not supported by the available data.

3 0
4 years ago
1. Approximate the given quantity using a Taylor polynomial with n3.
Jet001 [13]

Answer:

See the explanation for the answer.

Step-by-step explanation:

Given function:

f(x) = x^{1/4}

The n-th order Taylor polynomial for function f with its center at a is:

p_{n}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(n)}a}{n!} (x-a)^{n}

As n = 3  So,

p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{3!} (x-a)^{3}

p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{6} (x-a)^{3}

p_{3}(x) = a^{1/4} + \frac{1}{4a^{ 3/4} }  (x-a)+ (\frac{1}{2})(-\frac{3}{16a^{7/4} } ) (x-a)^{2} +  (\frac{1}{6})(\frac{21}{64a^{11/4} } ) (x-a)^{3}

p_{3}(x) = 81^{1/4} + \frac{1}{4(81)^{ 3/4} }  (x-81)+ (\frac{1}{2})(-\frac{3}{16(81)^{7/4} } ) (x-81)^{2} +  (\frac{1}{6})(\frac{21}{64(81)^{11/4} } ) (x-81)^{3}

p_{3} (x) = 3 + 0.0092592593 (x - 81) + 1/2 ( - 0.000085733882) (x - 81)² + 1/6  

                                                                                  (0.0000018522752) (x-81)³

p_{3} (x)  =  0.0092592593 x - 0.000042866941 (x - 81)² + 0.00000030871254

                                                                                                       (x-81)³ + 2.25

Hence approximation at given quantity i.e.

x = 94

Putting x = 94

p_{3} (94)  =  0.0092592593 (94) - 0.000042866941 (94 - 81)² +          

                                                                 0.00000030871254 (94-81)³ + 2.25

         = 0.87037 03742 - 0.000042866941 (13)² + 0.00000030871254(13)³ +    

                                                                                                                       2.25

         = 0.87037 03742 - 0.000042866941 (169) +  

                                                                      0.00000030871254(2197) + 2.25

         = 0.87037 03742 - 0.007244513029 + 0.0006782414503 + 2.25

p_{3} (94)  = 3.113804102621

Compute the absolute error in the approximation assuming the exact value is given by a calculator.

Compute \sqrt[4]{94} as 94^{1/4} using calculator

Exact value:

E_{a}(94) = 3.113737258478

Compute absolute error:

Err = | 3.113804102621 - 3.113737258478 |

Err (94)  = 0.000066844143

If you round off the values then you get error as:

|3.11380 - 3.113737| = 0.000063

Err (94)  = 0.000063

If you round off the values up to 4 decimal places then you get error as:

|3.1138 - 3.1137| = 0.0001

Err (94)  = 0.0001

4 0
4 years ago
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