1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Natali5045456 [20]
2 years ago
14

Need help?!?!?!?!?!?

Mathematics
1 answer:
drek231 [11]2 years ago
3 0

Answer:

1) b = 7.4 yds

2) c = 14.9 yds

Step-by-step explanation:

1) 3^2 + b^2 = 8^2

9 + b^2 = 64

b^2 = 64 - 9

b = sqrt 55

b = 7.4 yd

2) 15^2 + 2^2 = c^2

225+4=c^2

Sqrt(221) = c

C = 14.9

You might be interested in
The letter tiles shown below are in a bag. Without looking i am going to draw one tile.
TiliK225 [7]
D. 0.75 is the correct answer 

explanation- 2 out of the 8 tiles are not blue A. so 6 out of 8 tiles would round equal 75% chance of not getting a blue A tile 

<span />
8 0
3 years ago
Read 2 more answers
10. Write in slope-intercept form:<br> -3x + 4y = 12
Anastasy [175]

Answer:

Step-by-step explanation:

Write in slope-intercept form:

-3x + 4y = 12 is

 Slope = 1.500/2.000 = 0.750

 x-intercept = 12/-3 = 4/-1 = -4.00000

 y-intercept = 12/4 = 3

7 0
3 years ago
Sam has nine yellow pencils in his desk 3/4 of his pencils are yellow how many pencils does Sam have in his desk
mrs_skeptik [129]

Answer:

12

Step-by-step explanation:

(# of pencils)x(3/4)=9

(# of pencils)x(0.75)=9

(# of pencils)=9/(0.75)=12

3 0
3 years ago
What is the following quotient?
RideAnS [48]

Answer:

the third one i just took the test

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Working for a car company, you have been assigned to find the average miles per gallon (mpg) for acertain model of car. you take
Orlov [11]

Answer:

a) The 95% confidence interval for the mean mpg, for the certain model of car is (23.3, 30.1). This means that we are 95% sure that the true mean mpg of the model of the car is between 23.3 mpg and 30.1 mpg.

b) Increasing the confidence level, the value of T would increase, thus increasing the margin of error and making the interval wider.

c) 37 cars would have to be sampled.

Step-by-step explanation:

Question a:

We have the sample standard deviation, and thus, the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 15 - 1 = 14

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 14 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.1448

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.1448\frac{6.2}{\sqrt{15}} = 3.4

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 26.7 - 3.4 = 23.3 mpg.

The upper end of the interval is the sample mean added to M. So it is 26.7 + 3.4 = 30.1 mpg.

The 95% confidence interval for the mean mpg, for the certain model of car is (23.3, 30.1). This means that we are 95% sure that the true mean mpg of the model of the car is between 23.3 mpg and 30.1 mpg.

b. What would happen to the interval if you increased the confidence level from 95% to 99%? Explain

Increasing the confidence level, the value of T would increase, thus increasing the margin of error and making the interval wider.

c. The lead engineer is not happy with the interval you constructed and would like to keep the width of the whole interval to be less than 4 mpg wide. How many cars would you have to sample to create the interval the engineer is requesting?

Width is twice the margin of error, so a margin of error of 2 would be need. To solve this, we have to consider the population standard deviation as \sigma = 6.2, and then use the z-distribution.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How many cars would you have to sample to create the interval the engineer is requesting?

This is n for which M = 2. So

M = z\frac{\sigma}{\sqrt{n}}

2 = 1.96\frac{6.2}{\sqrt{n}}

2\sqrt{n} = 1.96*6.2

\sqrt{n} = \frac{1.96*6.2}{2}

(\sqrt{n})^2 = (\frac{1.96*6.2}{2})^2

n = 36.9

Rounding up:

37 cars would have to be sampled.

8 0
3 years ago
Other questions:
  • Find each unit rate <br> 1)78mi on 3gal<br> 2)$52.50 in 7 hours<br> 3)416 mi in 8 hours
    8·1 answer
  • The amount of time it takes to complete a reading assignment might be a
    12·1 answer
  • I need help ❤❤ please
    9·2 answers
  • What’s the domain and range
    13·1 answer
  • Mr Daniels is organizing a class field trip on a budget of $900.The bus rental costs $600. Mr.daniels will also buy tickets that
    6·2 answers
  • 9. Ellen is making gift baskets for four friends. She has
    15·2 answers
  • Is the following situation represented by a positive integer, a negative integer, or zero?
    12·1 answer
  • HELP FAST!!!!!!!!!!!!!
    15·1 answer
  • Solve for the missing variable. Round to the nearest tenth.
    6·1 answer
  • An automobile travels 140 miles in 4 hours. Find the average rate of speed
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!