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zzz [600]
3 years ago
12

Which expression is equivalent to sqrt 8/x^6. assume x > 0

Mathematics
2 answers:
Naddik [55]3 years ago
3 0
We have the following expression:
 sqrt 8 / x ^ 6
 Rewriting we have:
 sqrt (8 / x ^ 6)
 sqrt (2 * 4 / ((x ^ 2) * (x ^ 2) * (x ^ 2)))
 (2 / (x * x * x)) sqrt (2)
 (2 / x ^ 3) * sqrt (2)
 Answer:
 
An equivalent expression is given by:
 
(2 / x ^ 3) * sqrt (2)
labwork [276]3 years ago
3 0

Answer:

2 square root of 2 / x^3

Step-by-step explanation:

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A gas station sells 1600 gallons of gasoline per hour if it charges $ 2.70 per gallon but only 900 gallons per hour if it charge
kakasveta [241]

Answer:

Look just at finding the linear model. Two points. Use price per gallon for x and gallons per hour sold for y. Your two points (x,y) are (2.15,1600) and (2.55,800).

Slope m=%281600-800%29%2F%280.15-0.55%29

m=800%2F0.40

m=2000

Using point-slope form for a line, and the lower-y point,

y-800=2000%28x-2.55%29

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3 years ago
On a piece of paper, graph this system of inequalities. Then determine which region contains the solution to the system.
kirill115 [55]
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3 years ago
Conservation of Species A certain species of turtle faces extinction because dealers collect truckloads of turtle eggs to be sol
JulijaS [17]

Answer:

The turtle population's rate of growth will be 32 turtles per year after 2 years and 248 per year after 6 years.

Ten years after the conservation measures are implemented the population will be 3260 turtles.

Step-by-step explanation:

To find the rate of growth of the turtle population at any time <em>t</em> you need to find N'(t)

\frac{d}{dt}N(t)=\frac{d}{dt}(2t^3+3t^2-4t+1000)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\\frac{d}{dt}(2t^3)+\frac{d}{dt}(3t^2)-\frac{d}{dt}(4t)+\frac{d}{dt}(1000)\\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}\\\\N'(t)=6t^2+6t-4

In particular, when t = 2 and t = 6, we have

N'(2)=6(2)^2+6(2)-4=32\\\\N'(6)=6(6)^2+6(6)-4=248

so the turtle population's rate of growth will be 32 turtles per year after 2 years and 248 per year after 6 years.

The turtle population at the end of the tenth year will be

N(10)=2(10)^3+3(10)^2-4(10)+1000\\N(10)=3260 \:turtles

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3 years ago
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2/5 = 0.4 as a decimal.

Now subtract:

10.25 - 7.4 = 2.85 ounces are left

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3 years ago
Identify the following series as arithmetic, geometric, both, or neither. ​
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I think that is arithmetic i not totally sure
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