Answer:
the correct answer is choice D. if 24 precent of the snack mix is pretzels we simply need to multiply the total number of ounces by 0.24 7.68 ounces of the snack mix will be pretzels
Supposing the temperature of 60 degrees increases twice, it becomes 120 degrees (100% increase) and the bottles increase twice as well to 150 bottles (100% increase).
If there are 120 bottles used, we can calculate the temperature using the above assumption when bottle usage increase to 100% which is 150 bottles.
120 bottles/ 150 bottles = 0.8 or 80%
So, if 100% increase in temperature is defines by 120 degrees, what is 80% of 120 degrees?
Then 120 degrees divided by 0.8 will result to 96 degrees (so the answer is letter D) -- the temperature when 120 bottles were used by athletes.
Answer:
(24y^3x-20y^5x^2)/(-3y^5x^2)
= y^3x(24-20y^2x))/(-3y^5x^2)
=(24-20y^2x)/(-3y^2x)
=(24/(-3y^2x))-((20y^2x)/(-3y^2x))
=(-8/y^2x)-(-20/3)
=-8/y^2x + 20/3
So here the denominator is 5 and the numerator is 3. If you double 3, you get 6 and to make the fraction equal to 1, you have to make the denominator 6. So we do 6-5 which is 1
L*W*H
take them all and multipy
