Answer:
![BN=4\ \text{in}](https://tex.z-dn.net/?f=BN%3D4%5C%20%5Ctext%7Bin%7D)
![AN=2\ \text{in}](https://tex.z-dn.net/?f=AN%3D2%5C%20%5Ctext%7Bin%7D)
![AC=\sqrt{5}\ \text{in}](https://tex.z-dn.net/?f=AC%3D%5Csqrt%7B5%7D%5C%20%5Ctext%7Bin%7D)
Step-by-step explanation:
Let ![BN=x](https://tex.z-dn.net/?f=BN%3Dx)
![BC=c](https://tex.z-dn.net/?f=BC%3Dc)
![NC=y=1\ \text{in}](https://tex.z-dn.net/?f=NC%3Dy%3D1%5C%20%5Ctext%7Bin%7D)
![AB=a=2\sqrt{5}\ \text{in}](https://tex.z-dn.net/?f=AB%3Da%3D2%5Csqrt%7B5%7D%5C%20%5Ctext%7Bin%7D)
![AC=b](https://tex.z-dn.net/?f=AC%3Db)
We have the relation
![\dfrac{BC}{AB}=\dfrac{AB}{BN}\\\Rightarrow \dfrac{c}{a}=\dfrac{a}{x}\\\Rightarrow c=\dfrac{a^2}{x}\\\Rightarrow x+1=\dfrac{a^2}{x}\\\Rightarrow x^2+x=20\\\Rightarrow x^2+x-20=0\\\Rightarrow x=\frac{-1\pm \sqrt{1^2-4\times 1\times \left(-20\right)}}{2\times 1}\\\Rightarrow x=4,-5](https://tex.z-dn.net/?f=%5Cdfrac%7BBC%7D%7BAB%7D%3D%5Cdfrac%7BAB%7D%7BBN%7D%5C%5C%5CRightarrow%20%5Cdfrac%7Bc%7D%7Ba%7D%3D%5Cdfrac%7Ba%7D%7Bx%7D%5C%5C%5CRightarrow%20c%3D%5Cdfrac%7Ba%5E2%7D%7Bx%7D%5C%5C%5CRightarrow%20x%2B1%3D%5Cdfrac%7Ba%5E2%7D%7Bx%7D%5C%5C%5CRightarrow%20x%5E2%2Bx%3D20%5C%5C%5CRightarrow%20x%5E2%2Bx-20%3D0%5C%5C%5CRightarrow%20x%3D%5Cfrac%7B-1%5Cpm%20%5Csqrt%7B1%5E2-4%5Ctimes%201%5Ctimes%20%5Cleft%28-20%5Cright%29%7D%7D%7B2%5Ctimes%201%7D%5C%5C%5CRightarrow%20x%3D4%2C-5)
![\boldsymbol{BN=4\ \text{in}}](https://tex.z-dn.net/?f=%5Cboldsymbol%7BBN%3D4%5C%20%5Ctext%7Bin%7D%7D)
![h=\sqrt{a^2-x^2}\\\Rightarrow h=\sqrt{(2\sqrt{5})^2-4^2}\\\Rightarrow h=2\ \text{in}](https://tex.z-dn.net/?f=h%3D%5Csqrt%7Ba%5E2-x%5E2%7D%5C%5C%5CRightarrow%20h%3D%5Csqrt%7B%282%5Csqrt%7B5%7D%29%5E2-4%5E2%7D%5C%5C%5CRightarrow%20h%3D2%5C%20%5Ctext%7Bin%7D)
![\boldsymbol{AN=2\ \text{in}}](https://tex.z-dn.net/?f=%5Cboldsymbol%7BAN%3D2%5C%20%5Ctext%7Bin%7D%7D)
![b=\sqrt{h^2+y^2}\\\Rightarrow b=\sqrt{2^2+1^2}\\\Rightarrow b=\sqrt{5}\ \text{in}](https://tex.z-dn.net/?f=b%3D%5Csqrt%7Bh%5E2%2By%5E2%7D%5C%5C%5CRightarrow%20b%3D%5Csqrt%7B2%5E2%2B1%5E2%7D%5C%5C%5CRightarrow%20b%3D%5Csqrt%7B5%7D%5C%20%5Ctext%7Bin%7D)
![\boldsymbol{AC=\sqrt{5}\ \text{in}}](https://tex.z-dn.net/?f=%5Cboldsymbol%7BAC%3D%5Csqrt%7B5%7D%5C%20%5Ctext%7Bin%7D%7D)
Step one: multiply and divide in order.
Step two: add and subtract like terms.
Step three: get X alone on one side (what you do to one side you have To do to the other side)
Step four: simplify and solve :)
I got 5 times 45 because I multiplied by 5 to get my answer.
you can just split the figure in 2 separate figures and them add the areas:
area rec. 1:
3m×3m= 9m²
area rec. 2:
3m× (2m+3m)
= 3m×5m
=15m²
total area:
9m²+15m²= 24m²
Answer:
The answer is "3"
Step-by-step explanation:
In the question, some of the data is missing which is defined in the attached file. please find it.
![\to 7+(-4)\\\\\to 7-4\\\\\to 3](https://tex.z-dn.net/?f=%5Cto%207%2B%28-4%29%5C%5C%5C%5C%5Cto%207-4%5C%5C%5C%5C%5Cto%203)
That's why 3 is correct.