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Sergeeva-Olga [200]
3 years ago
14

Tickets for the slide cost $1. Tickets for the Ferris wheel cost $2. Stephen and Alicia went on each ride the same number of tim

es. Together, they spent $12. How many times did they go on each ride ?
Mathematics
2 answers:
Kipish [7]3 years ago
4 0
They went on the slide 6 times and they went on the ferries wheel 3 times(1x6=6 2x3=6)
bagirrra123 [75]3 years ago
3 0
They each went on the ferries wheel and slide 2 times. 2x2x2 and 1x2x2
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The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E
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Answer:

The projected enrollment is \lim_{t \to \infty} E(t)=10,000

Step-by-step explanation:

Consider the provided projected rate.

E'(t) = 12000(t + 9)^{\frac{-3}{2}}

Integrate the above function.

E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt

E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c

2000=-\frac{24000}{3}+c

2000=-8000+c

c=10,000

Therefore, E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

Now we need to find \lim_{t \to \infty} E(t)

\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

\lim_{t \to \infty} E(t)=10,000

Hence, the projected enrollment is \lim_{t \to \infty} E(t)=10,000

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