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sveticcg [70]
3 years ago
12

600 divided by 15 is the same as

Mathematics
1 answer:
Lemur [1.5K]3 years ago
8 0

Answer:

is there more to the question?

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To the nearest tenth of a degree, find the sizes of the acute angles in the 5-12-13 triangle and in the 9-12-15 triangle. This e
Paha777 [63]

Answer:

Step-by-step explanation:

A triangle whose sides are 5-12-13 is a right angle triangle because the sides form a Pythagoras triple. This means that

Hypotenuse² = opposite side² + adjacent side²

If hypotenuse = 13,

Opposite side = 12, then we can determine one acute angle by applying the sine trigonometric ratio

Sin θ = opposite side/adjacent side

Sin θ = 12/13 = 0.923

θ = Sin^-1(0.923) = 67.4°

The other acute angle is

90 - 67.4 = 22.6°

For 9-12-15 triangle

Sin θ = 12/15 = 0.8

θ = Sin^-1(0.8) = 53.1°

The other acute angle is

90 - 53.1 = 36.9°

For 13- 14-15 triangle,

Sin θ = 14/15 = 0.933

θ = Sin^-1(0.933) = 68.9°

The other acute angle is

90 - 68.9 = 21.1°

Another example would be 3-4-5

Sin θ = 4/5 = 0.933

θ = Sin^-1(0.8) = 53.1°

The other acute angle is

90 - 53.1 = 36.9°

3 0
3 years ago
Which of the following is a third root of the given complex number? 27(cos(pi/5)+isin(pi/5))
Digiron [165]
<span>The third root of the given complex number 27(cos(pi/5)+isin(pi/5)) is <span>3(cos(pi/15)+i sin(pi/15)) 

</span>The solution would be like this for this specific problem:</span>   <span>2^5 = 32 so you need a 2 out front the 5th root of cos(x) + i sin(x) is cos(x/5) + i sin(x/5). Additionally, 5 roots are located at even intervals around the circle. They are spaced every 2 pi/5 or 6 pi/15 radians. </span>   <span>Roots are located at pi/15, pi/15+ 10pi/15 = 11 pi/15 and pi/15+ 20pi/15 = 21 pi/15 (or 7 pi /5 ).</span>
5 0
4 years ago
Find the missing side lengths and leave your answers as radicals in the simplest form.
goblinko [34]
Right triangle 45 45 90
so b = 2√2

and
a^2 = (2√2)^2 +  (2√2)^2
a^2 = 8 + 8 
a^2 = 16
a = 4
3 0
3 years ago
Read 2 more answers
I have 30 ones, 82 thousands, 4 hundred thousands, 60 tens, and 100 hundreds. What number am I?
stich3 [128]
This problem tackles the place values of numbers. From the rightmost end of the number to the leftmost side, these place values are ones, tens, hundreds, thousands, ten thousands, hundred thousands, millions, ten millions, one hundred millions, and so on and so forth. My idea for the solution of this problem is to add up all like multiples. In this problem, there are 5 multiples expressed in ones, thousands, hundred thousands, tens and hundreds. Hence, you will add up 5 like terms. The solution is as follows

30(1) + 82(1,000) + 4(100,000) + 60(10) + 100(100)

The total answer is 492,630. Therefore, the number's identity is 492,630.
7 0
3 years ago
PLEASE I NEED HELP ASAP THIS IS ALSO MIDDLE SCHOOL/ pancho writes a check for $140 a month for the electric bill. He writes anot
Margaret [11]

Answer:

140x12+105x4+55x12= 86,340 a month

Step-by-step explanation:

7 0
2 years ago
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