Put a dot in the middle and put a line up on one side and across the sides
Answer:
3
Step-by-step explanation:
Wire is 4 1/2 feet, or 4.5 feet.
Each smaller wire needs to be 1 1/4 feet, or 1.25 feet.
<em>How many whole 1.25 feet wire can we have from total of 4.5 feet wire?</em>
<em />
Let's divide:
\![\frac{4.5}{1.25}=3.6](https://tex.z-dn.net/?f=%5Cfrac%7B4.5%7D%7B1.25%7D%3D3.6)
<em>thus we can have 3 whole "1.25 feet long" wire and fractional amount.</em>
<em />
<em>Hence, maximum number of smaller pieces is 3</em>
Answer:
![\approx 118.4](https://tex.z-dn.net/?f=%5Capprox%20118.4)
Step-by-step explanation:
We know two sides and the angle between the sides, so we can use the Law of Cosines. Recall that the Law of Cosines states that:
, where a and b are the sides and C is the angle in between.
Let's substitute 115 for a, 178 for b, and 41 for Angle C.
Thus:
![c^2=115^2+178^2-2(115)(178)cos(41)](https://tex.z-dn.net/?f=c%5E2%3D115%5E2%2B178%5E2-2%28115%29%28178%29cos%2841%29)
![c^2=44909-40940cos(41)](https://tex.z-dn.net/?f=c%5E2%3D44909-40940cos%2841%29)
![c=\sqrt{44909-40940cos(41)}](https://tex.z-dn.net/?f=c%3D%5Csqrt%7B44909-40940cos%2841%29%7D)
![c \approx 118. 4](https://tex.z-dn.net/?f=c%20%5Capprox%20118.%204)
The line from the point to its reflection should be perpendicular.If we imagine a line from (5,7) to (2,2), it would have a slope of (2-7)/(2-5) = 5/3.
For that line to be perpendicular to y=-2/5x+6, their slopes should be each other's negative reciprocals.
-2/5 negative reciprocal is 5/2, which is not equal to our calculated 5/3, so (2,2) cannot be the reflected point. Evan was wrong.
Q1-74: AB have slope 6/5, C has -5/6, D 6/5, E -5/6 again.
Hey again!
The answer to your question is 10 meters.
We can solve this by multiplying 15 and 2/3, and you get 10
Hope it helps!