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Ghella [55]
3 years ago
9

What’s the answer this is hard

Mathematics
1 answer:
Vanyuwa [196]3 years ago
5 0

Answer:

Lowest point y = -2, highest point = 6

Step-by-step explanation:

The given function is g(t) = 4sin (3t) + 2

When we plot the function on a graph we use the sine graph y = a sin(bx+c) + d. Here a is amplitude, c is horizontal shift and d is vertical shift.

Therefore in this function d is 2 so sine graph is vertically shifted of we can say y = 2 is the center line  

Here in the given function amplitude of the sine wave is 4.

The lowest point on the graph will be y = 2-4 = -2

The highest point of the graph will be y = 2+4 = 6

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Since this equation defines a hyperbola, we expect the asymptotes to be lines of the form p(x)=ax+b.

Ignore the negative root (we don't need it). If y=2x-1+2\sqrt{x^2-x}, then we want to find constants a,b such that

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The other asymptote is obtained similarly by examining the limit as x\to-\infty.

\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0

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