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3 years ago

(1 point) find three positive real numbers whose sum is 37 and whose product is a maximum.

Mathematics

1 answer:

zysi [14]3 years ago

5 0

Yes it is courtesy blah blah black black lack

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A tree casts a shadow 27 m long. At the same time, the shadow cast by a 66-cm tall statue is 56 cm long. Find the height of the

Nata [24]

$\frac{height _{1} }{shadow_{1}} = \frac{height _{2} }{shadow_{2}}$

$\frac{height _{1} }{27m} = \frac{66cm}{56cm}$

$\frac{height _{1} }{2700cm} = \frac{66cm}{56cm}$

$2700*66=56*h _{1}$

$178200=56h _{1}$

$3182.1cm=h _{1}$

$\frac{3182.1cm}{1000cm} = 3.2m$

$height:3.2m$

6 0

3 years ago

Read 2 more answers

If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

8 0

3 years ago

200 is 10 times as much as blank and 1 tenth of

anzhelika [568]

Answer:

200 is 10 times as much as 20 and 1 tenth of 2,000

Step-by-step explanation:

Divide 200 by 10 and you'll get 20 and multiply it by 10 to get 2,000.

8 0

3 years ago

Read 2 more answers

Simplify (x^2 -25)/ (2x^2-7x-15)

murzikaleks [220]

Answer:

$\frac{x+5}{2x+3}$

Step-by-step explanation:

4 0

3 years ago

At oceanside middle school 110 students tried out for the football team only 80% of the students that tryout make the team how m

Olenka [21]

Step-by-step explanation:

answer is 22 students in the team

how do u get it? 

you know it is 80% of the students went for try out so you do 100% - 80% give you 20% students the number of students in the team already. so you do 20 / 100 x 110 students which already in the whole school over 1 which would give it 22

3 0

2 years ago