<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>3</em><em>.</em>
<em>look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
<em>~</em><em>p</em><em>r</em><em>a</em><em>g</em><em>y</em><em>a</em>
Answer:
f(1)=-11
f(n)=f(n-1)+22
Step-by-step explanation:
Base equation:
f(n)=-11+22(n-1)
f(1)=-11+22(1-1)
f(1)=-11+0
f(1)=-11
f(n)=-33+22n
f(n-1)=-11+22(n-2)
f(n-1)=-55+22n
-33+22n=-55+22n+x
22n gets canceled out
-33=-55+x
-33+55=x
x=22
f(n)=f(n-1)+22
Answer:
Derivative: P’(x) = 200 - 2x
If P’(x) = 0 , x = 100
Therefore P’ is positive and P increases until x = 100
So the maximum units to maximize profits is 100 units
And for 100 units the profit in dollar is:
20000 - 10000 = 10000
10000 dollars
Step-by-step explanation:
The first expression is :
Numerator = -11×2 = -22
Denominator = 3
So, answer will be :
(negative)
The second expression is:
Numerator = -11×-2 = 22
Denominator = 3
So, the answer will be :
(positive)
Hence, this is the required solution.
The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma(
)
E(X)= 
= 
=6 weeks
V(x)= 
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X, , , False)
P(
)
P(
)
P(
)
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
To learn more about probability click here:
brainly.com/question/11234923
#SPJ4
